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Ch.7 - Covalent Bonding and Electron-Dot Structures

Chapter 7, Problem 52

Show the direction of polarity for each of the bonds in Problem 7.51 using the notation. (b) Si-Li or Si-Cl

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well every once in this video are being asked which diagram correctly shows the direction of polarity between phosphorus and oxygen and phosphorus and hydrogen using our delta plus and delta minus notation. So for delta plus, this goes on the item that's less electro negative. As for our delta minus, this goes on our more electro negative atom. So these electro negativity values can be either found in your textbook given to you by a professor that have been found online. These are just values that I have. So starting off with phosphorus, we have a value of 2.1 auction, has a value of 3.5 and hydrogen has a value of 2.2. So taking a look at the bond of phosphorus and auction, you can see that phosphorus is more positive and auction is more negative because it has a higher electro negativity value. And then comparing phosphorus and hydrogen again, phosphorus is more positive and hydrogen is slightly more negative. So regardless of what the other item is between the oxygen, hydrogen phosphorus will always have this delta plus sign because it's less electro negative and more positive. So taking a look at a diagram, a then we see that the first phosphorus here is slightly negative and that's incorrect because we already see that regardless of what other adam Foster is connected to, they will have a slightly positive charge. So I delta plus now for a statement be both phosphorus does have a slightly or delicate plus sign. This is correct. We go ahead and move on to see both of our phosphorus has a delta negative notation. That's incorrect. Unless the first diagram D here, we see that between our phosphorus and hydrogen, this phosphorus has a delta minus, so that is again incorrect. So the only diagram that correctly represents our polarity between phosphorus oxygen and phosphorus and hydrogen is going to be diagram B, and that's going to be my final answer for this problem.