Which of the following substances contain bonds that are largely ionic? (a) HF (b) HI (c) PdCl2 (d) BBr3 (e) NaOH (f) CH3Li

Video transcript

Welcome back everyone we need to determine based on the substances below which has the largest ionic bond character. So we're going to recall that the greater the difference in electro negativity that will correspond to a greater ionic bond character. So we're going to be referencing our textbooks to find the electro negativity values for each of the atoms that make up the the ionic compounds A through D. So beginning with compound A. We have hydro bronek acid and we're going to begin with the election negativity For hydrogen, which in our textbooks will see has a value of 2.2 And then finding the election negativity for bromine, we would see that corresponds to a value of 2.8. And so taking that difference to find the difference in electro negativity, we would have our higher value 2.8 subtracted from 2.2. And that's going to give us a election negativity difference of . for hydroponic acid. So moving on to our next compound, we have silver bromide. So beginning with our electro negativity value for our silver atom in our textbooks, we see that that's a value of 1.9. And then for our electro negativity value of bromine in our textbooks, that's a value of 2.8. So finding the electro negativity difference, we have 2.8 -1.9 to give us a value of .9. Next we have our election negativity of hydrogen in our molecule water, which, as we stated earlier is a value of 2.2. And then for our election negativity value of oxygen in our textbooks we see that that's 3.5. So finding the election negativity difference in our compound water, we have 3.5 -2.2 to give us a difference of 1.3. So right now we can already rule out choices a and b. Since they're less than 1.3. And we know that the greater the election negativity difference means a greater ionic bond character. So let's move on to choice d aluminum three chlorine, chloride. So we have the election negativity value for aluminum which in our textbooks we see is equal to 1.5 and then our election negativity value for chlorine which in our textbooks we see is a value of three until finding the election negativity difference here We see we have the difference of 3 -1.5, which will give us a value of 1.5. And because we see that 1.5 is greater than 1.3 we can rule out choice d. Anying that aluminum three chloride is the substance that has the largest ionic bond character since it has election negativity difference of 1.5. So I hope that everything I reviewed was clear. If you have any questions please leave them down below and I'll see everyone in the next practice video