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Ch.7 - Covalent Bonding and Electron-Dot Structures

Chapter 7, Problem 42

Explain the difference in the bond dissociation energies for the following bonds: (C-F, 450 kJ/mol), (N-F, 270 kJ/mol), (O-F, 180 kJ/mol), (F-F, 159 kJ/mol).

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everyone in this video, we're being told that the bond dissociation energy decreases from hydrogen fluoride. All the way to hydro biotic acid. We're trying to see from these four different statements why this occurs. So we can kind of evaluate these four different molecules by considering the electro negativity difference. So we go ahead and calculate those starting off with hydrogen fluoride. So I'll represent the difference as delta E. N. So delta means the change of and then E. N. Is just short for electro negativity. So looking at my chart that I have and you can also go ahead and fall along with either the chart from the given text book. It can either be given to you by a professor or it can be even found online. I'm receiving values that I have. So for electro negativity of flooring, that's 4.0 and hydrogen has a value of 2.1. So taking the difference between these two is equal to 1.9. Next will be H. C. L. So chlorine has a value of 3.0 and hydrant has a value of 2.1. Taking a difference of these two, we get 0.9. Next we go ahead and value eight H. B. R. So Brandon has a value electro negativity value of 2.8 and hydrogen has a value of 2.1. The difference of those is 0.7 in our last asset here, H.I So I didn't have a value of 2.5. While hydrant has a value of 2.1. So the difference of those two is 0.4. So we know now that the more polar the bond is, the stronger the bond is. So basically we have a direct relationship and that's why we see that when polarity increases or decreases the bond dissociation energy also increase or decrease along with them. So there's a direct relationship. So out of these four different statements here, we can see first for A that this does not relate to us because all of our bonds are only sigma bonds are just single bonds, so this is automatically canceled. And for B, the state that we have a direct relationship, it has an inverse relationship. But we already said here that we have a direct relationship, so B. Is also eliminated. And of course that leaves us with C saying that the polarity of the bond decreases, which results in a decrease in bond strength, and this does represent a direct relationship. Therefore, statement. See here is going to be the correct answer for this problem.