What noble-gas configurations and charge are the following elements likely to attain in reactions in which they form ions? (b) Ca

Video transcript

Hello everyone today. We are being given the falling problem provide the noble gas configuration and the charge of the ion most likely formed by barium. So the first thing you want to do is we want to note the atomic number of barium and if we go on the periodic table, we can note that the atomic number of barium is 56. And since this is neutral, that indicates that we have 56 electrons. We should also note that barium is in the 6th period or period six with the rose. And so in constructing the noble gas configuration right, our noble gas configuration or config for short, we're gonna start with the noble gas before bury him. That is going to be Xenon. And so a neutral Barium is going to be our noble gas in brackets Xenon followed by our orbital that we're in for barium. So we said barium is in the sixth period. So it's going to have a six S and it's the second element in that s orbital. So it's gonna be six S two. And so this is going to be our noble gas configuration for barium. We'll keep note of that. So Bury him is a group two elements Group two way to be specific. But for this question, we just need to know that this group too. And so what that means is that it will lose two electrons from the highest orbital. And so where are those two orbiters going to be lost? They're going to be lost in that six S orbital because that exponent represents the number of electrons. And so if we take away those two electrons, we will be left with simply our xenon. And this is going to represent Our barium two plus. That's going to be our ion. The electron configuration for our ion that's formed is going to be this xenon here, Followed by the ion being barium two plus, denoting that we lost two electrons because electrons are negatively charged. And with that we've answered the question overall, I hope that this helped and until next time.