Three binary compounds are represented on the following drawing: red with red, blue with blue, and green with green. Give a likely formula for each compound.

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Welcome back everyone in this example, the given diagram depicts three possible binary compounds. One blue with violet to red with green and three yellow with orange provide a possible chemical formula for each compound. Beginning with part one, we have the combination of blue with violet and so looking at first the blue box, we recognize that it's an atom and group foray across period two of our periodic table which we would see corresponds to the atom carbon. And so recall that because carbon is in group four A. It could have the potential of forming ions as plus four or minus four. So can any other ataman group for a form either of these charged ions or? None at all. Now moving on to the violet colored box in the diagram we have an atom located in Group seven A. Which lies across period three referring to our periodic table. We would see that that corresponds to the atom being chlorine, recall that any atom in Group seven A will form a minus one an ion charge potentially. So now writing out these two atoms, we have the combination of carbon and chlorine which based on their positions on the periodic table are both non metals. Recall that when we have the combination of two non metals, this means that we have an ionic compound, meaning that we would have a transfer of electrons. And so if we have these ions that form either being the C plus four caddy on or the cl minus one an ion since we have a transfer of electrons, we're going to cross these charges with both of these atoms, Which is going to allow us to form the compound CCL four where chlorine gets that plus four charge from our carbon atom. And so for our first answer, we have carbon tetrachloride as our binary compound. We call that a binary compound. Just means it consists of two different atoms moving on to set to. We have the combination of red with green. Looking at our diagram above focusing on the red box. First we have an atom in Group four A which lies across period five of our periodic table. We would see that corresponds to the atom being tin sn. Then focusing on the green box. We have an atom in Group six A which lies across period two. We would see that this corresponds to the atom of oxygen. So we have tin and oxygen for the red block and the green block recognized that oxygen because it's in group six A has the potential to form a minus to an ion charge. So combining tin and oxygen, recognizing that tin based on its position on the periodic table is a metal and oxygen based on its position is a non metal. We would have the combination of a metal and non metal which would give us a co violence or molecular compound, we would recall that means that we share electrons between the atoms and so we would have either the formation of tin without any ion charge. Since it doesn't always have to form ions with our oxygen atom which could potentially form a two minus an ion charge. So transferring or rather sharing the electrons here, we would form the compound 10 four oxide. So 02. And we know that this is 10 4 oxide. Because we would recall that tin based on its position on the periodic table is considered a transition metal, meaning it could have multiple ionic charges. And because it doesn't always have to form a ionic charge, we could also end up with the compound tin oxide. S. N. O. Now moving on to set three. What we just determined our our next two final answers. Now moving on again to set three. From the prompt set three is yellow with orange. So we have we'll just write yellow and black plus orange. We'll just use pink. So looking at our periodic table or diagram given we have an atom that is the yellow colored box in group two A. Across period four, we would see that this corresponds to the atoms calcium on our periodic tables. Next focusing on the orange box, we have an atom in group seven A which lies across period four which we see would correspond to the halogen atom bromine. Recall that group seven A. As our halogen group. So we have the combination of calcium and we have the combination of calcium with bromine recognized that bromine is considered a non metal based on its position, whereas calcium is considered a metal based on its position on the periodic table, which again means that we have a covalin or molecular compound, meaning we'll share electrons between these two atoms. We also want to make note of the fact that because calcium is in group two a. It will likely form a plus to caddy on charge. So moving on to figure out our compound, we have the combination of A C, A two plus catalon and a B. R -1, an ion which in a covalin compound would be sharing these electrons. And so we would have our single electron on bro mean being shared with calcium and so we have C. A. And then the two missing electrons from calcium will be fulfilled by bromine. So we would have BR two. And so now this is going to be our compound. We recognize as calcium bromide, which is our fourth final answer as our last binary compound. So what's highlighted in yellow are our final answers of binary compounds based on our given diagram. I hope everything I reviewed was clear. If you have any questions, leave them down below and I will see everyone in the next practice video

Three binary compounds are represented on the following drawing: red with red, blue with blue, and green with green. Give a likely formula for each compound.

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Key Concepts

Binary Compounds

Chemical Formulas

Color Coding in Chemistry