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Ch.6 - Ionic Compounds: Periodic Trends and Bonding Theory

Chapter 6, Problem 46

There are two elements in the transition-metal series Sc through Zn that have four unpaired electrons in their 2+ ions. Identify them.

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Hello everyone today. We are being given the following problem identified two elements with two unpaid electrons in their three plus ions found in the scan diem to zinc transition metal series. So first let's define where our transition metals are. So our transition metals are going to be found within our D orbital's. And so we know from this problem that are charged ions are going to be three plus or plus three and our possible noble gas configurations are going to be argon. Since that is the noble gas. Just before we enter the transition metals three D. Because our transition metals start with three D N N N can be any sort of electron. And so we have two different possibilities for elements to have two unpaid shared electrons. So we know three d orbital's Or in general can hold 10 electrons total. And so we can have in the event where we have 123, 456, where we have these two unparalled electrons or we can have the case of simply 1, 2 with these unpowered electrons being so and so We said the possibility could be this argon three DN. So let's entertain this argon. This noble gas configuration and then having three D eight, three D eight is going to consist of our 18 electrons from Argon plus our eight electrons from the Exponent here. And this is going to give us a total of 26 electrons. It's important to note that the number of protons, any event that we have a charged species is a number of electrons plus whatever charge we have with us. And so in this event we have 26 electrons and a charge of plus three giving us a total number of Protons are being 29, which corresponds two Copper on the Periodic Table. and so a three plus ion Of copper is going to look as such copper three plus. And so this is actually going to be one of our answers. We then have to consider the possibility That we have our argon and brackets and then we have three D 2. So we have two electrons that are unpaid. And this is going from scan diem to zinc once more. And that's why we're choosing these numbers. So once again, Argon is going to have our 18 electrons plus our two that we have here. That's gonna give us 20 electrons total. As we said before, the number of protons in a charged species is going to equal the number of electrons plus the charge that we have. And in this case we have 20 electrons and our charge is plus three. This gives us the number of protons equaling 23, which aligns with vanadium on the periodic table or the and so a three plus ion of vanadium, It's going to look as follows. V three plus. And so our answer, it's going to be. And your choice a copper three plus and vandy um vanadium three plus. Since these are two elements with two unpaid electrons in the three plus ions found in the scan diem to zinc row on the periodic table. Overall, I hope that this helped, and until next time.