Consider the noble gas xenon. (a) Write the electron configuration of xenon using the abbreviation of the previous noble gas.

Video transcript

Hello everyone today, we have the falling problem. Krypton is one of the noble gasses using the preceding noble gas provide the electron configuration of the krypton. So first it's important to note what the atomic number of krypton is And its atomic number according to the periodic table is 36. And since it is neutral, this indicates that there are 36 electrons. It's also important to note that Krypton is in the 4th period. In constructing the noble gas configuration, we must take into account the noble gas that comes before that comes directly before our krypton. And that is Argon. Argon has 18 electrons. So for writing out the noble gas configuration, we're going to start out with our argon in brackets. And so if we have 18 used already when we have argon, that means we have 18 left. So we said that krypton is in the fourth period. So we're going to start off with our four, we're going to start with the s orbital. So we have four s too. Since we're filling in those first two electrons, we then moved to our three D orbital's because our D orbital's is always one less than the preceding s orbital and we're filling in all of those electrons. So that becomes a three D 10 and then we move back to the p orbital, we return back to the same energy level as our s orbital was. So we have for us and now we have four P. And so Krypton Is the 6th element in that four p orbital. And so that's going to lead us with this configuration right here and with that, we have answered the question overall, I hope that this helped, and until next time.