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Ch.5 - Periodicity & Electronic Structure of Atoms
Chapter 5, Problem 42

Calculate the energies of the following waves in kilojoules per mole, and tell which member of each pair has the higher value. (a) An FM radio wave at 99.5 MHz and an AM radio wave at 1150 kHz

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Electromagnetic Spectrum

The electromagnetic spectrum encompasses all types of electromagnetic radiation, which vary in wavelength and frequency. Radio waves, including FM and AM waves, are part of this spectrum and have longer wavelengths compared to visible light. Understanding the position of these waves within the spectrum is crucial for calculating their energy.
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Energy of a Photon

The energy of a photon is directly related to its frequency and can be calculated using the equation E = hν, where E is energy, h is Planck's constant, and ν is frequency. This relationship indicates that higher frequency waves possess greater energy. Thus, comparing the energies of FM and AM waves requires converting their frequencies into energy values.
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Conversion to Kilojoules per Mole

To express the energy of individual photons in kilojoules per mole, one must convert the energy calculated in joules to kilojoules and then multiply by Avogadro's number (approximately 6.022 x 10²³). This conversion is essential for comparing energies on a per-mole basis, which is a common practice in chemistry.
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