Predict whether a precipitation reaction will occur when aqueous solutions of the following substances are mixed. For those that form a precipitate, write the net ionic reaction. (a)

Video transcript

Hello everyone in this video. We're dealing with this reaction right over here. I was trying to find the net ionic reaction for those that produce a precipitate. So let's kind of rewrite this start materials so we can have a clear view. Alright, so we can see that we have a double displacement reaction here. And what that is is that of course for every molecule we have a heavy on and and on on pear. And what this means is that they're just basically be switching partners. So for example, 1st 1st product we will use the cat ion partner of Cape and then we'll switch the an ion um couple to B R B R and this is going to be Aquarius solution in solution. And in our second product will be our H with R. O. H. Which is just a church to oh and of course that's going to be liquid. So again, we're dealing with a double displacement so we're switching partners And this is how we got those two products now that we have this reaction here, let's go ahead and now right out the net are the ionic equation first. So we have our ionic equation. So the first one that we just wrote is just our balanced chemical reaction. Now we're writing out the ion equation. Alright, so the ionic reaction is if our products are reagents here are going to be a quiz, then they'll go ahead and associate into its ionic form when it's going to be mixed in a solution. Of course any solid or any liquids will just remain as is all right. Start off with the first agent here. R K O H. That's going to dissociate into its ionic form in solution. So that's just K plus and O H minus. And then for H B R. 04 again that is also Aquarius. So in solution would associate into H plus and B. R. 04 minus. Alright, now for our products here are KBr oh four, that's going to be a crea so it associated ionic forms of K plus and B. R. 04 minus. And then the water will just remain as is H. 20. All right, so now we'll find our next ionic equation which which is simplified to And E. So we're just removing spectator ions here and what that is is that its ions that repeat on both the star material side and product side. So I just rewrites are ionic equation and why I want to rewrite this is just so we can see the step by step more clearly. Alright, so let's go ahead to remove the spectator ions now. But I see repeating is going to be our K plus our B our foe and B. R. 04 and seems to be about it. So the net Ionic equation then must remove all the spectator ions is going to be our H minus, reacting with our H plus carry on. And that gives us our H20. And it's the good state. So this is going to be my final net ionic equation for this problem. It gives so much for watching.