How many moles of solute are present in each of the following solutions? (b) 175 mL of 0.67 M glucose (C₆H₁₂O₆)

Key Concepts

Molarity

Molarity (M) is a measure of concentration defined as the number of moles of solute per liter of solution. It is expressed in moles per liter (mol/L) and is crucial for calculating the amount of solute in a given volume of solution. In this question, the molarity of the glucose solution is given as 0.67 M, indicating that there are 0.67 moles of glucose in every liter of solution.

Volume Conversion

To calculate the number of moles of solute, it is essential to convert the volume of the solution from milliliters to liters, as molarity is defined in terms of liters. Since 1 liter equals 1000 milliliters, the volume of 175 mL can be converted to liters by dividing by 1000, resulting in 0.175 L. This conversion is a critical step in the calculation process.

Calculating Moles from Molarity

The number of moles of solute can be calculated using the formula: moles = molarity × volume (in liters). By multiplying the molarity of the solution (0.67 M) by the converted volume (0.175 L), one can determine the total moles of glucose present in the solution. This relationship is fundamental in stoichiometry and solution chemistry.