List three ways in which the properties of boron differ from those of the other group 3A elements.

Video transcript

Hello everyone. Today we have the following problem which of the following statements correctly differentiates boron from the other group three A elements we have a that says Boon is a nonmetal. While the other group three A elements are metals, B that says Boon cannot form a cion with a positive three charge. While the other group three A elements can c that says Boon forms both molecular and and ionic compounds. While the other group three elements only for ionic compounds. And D that says all of the above. So let's look at inventories. A first recall that metals are good conductors of electricity while non metals are poor conductors of electricity. And so you have what's known as a semi metal that is in between. So if we draw the symbol for boron, we say that boron is considered a semi metal due to its position on the periodic table. And so it has characteristics of both metals and nonmetals and they are generally used as good semiconductors, but they still have less connectivity than metals. And so if you look at the periodic table, boron is the only semi metal that belongs to group three A while the other elements in that group are metals. And so that makes Antos a incorrect as well as d if we move on to be, we can recall that metals tend to lose electrons and form cations while non metals gain electrons and form anions. So we said that metals can form Kelly Owens and non metals can form anions. Boon will not form a cion because it's not a metal and it will not form an anion because it is not a non metal. And so if we were to also take into account the atomic radius of boron, that's relatively small and it also has a high ionization energy. So we say that boron has a small atomic radius and a very large ionization energy. And that means that it is very difficult to pull electrons from boron's electron cloud. And so if we look at the other elements in group three A, they are metals and they will therefore form a counting on with a positive three charge. So we can say that Android B is actually the correct answer. But if we look at C, we can just say that Boon cannot form molecular Orion compounds because it is a semi metal and also has a high ionization energy as well as a small atomic radius. While the other elements in group three A have a larger atomic radius and a lower ionization energy, meaning that it is easier for them to lose electrons. And form ionic compounds making answer to c incorrect. And so with that, we have r, with the answer, with answer B overall, I hope it's helped. And until next time.