Complete and balance the equation for each of the following reactions.

d. $C_2H_6\left(g\right)+H_2O\left(g\right)\overset{heat}{\underset{catalyst}\rightarrow}$

Video transcript

Hello, everyone. Today, we have the following problem. Predict the products formed and provide the complete balanced equation for the following reaction. So here we have a hydrocarbon reacting with water with heat and a catalyst. And this is called a steam hydrocarbon reforming process. And this reaction will form a mixture of carbon monoxide gas as well as hydrogen caps. So former answer choices, we see that the products consist of carbon monoxide and hydrogen gas and then carbon dioxide and hydrogen gas. So we know that answer choices C and D can be eliminated because we are dealing with hydro carbon monoxide. So for balancing, we have to look on each side of the reaction arrow for how many of each atom we have. So we have carbons, hydrogens and oxygens. On the left of our reaction arrow, we have four carbons and on the right, we have one on the left, we have 12 hydrogens and on the right, we have two and then we have one oxygen on the left and we have one on the right. So the first thing we want to balance is our carbons. And so we simply need to add a coefficient of four to the carbon monoxide. And that multiplies our coefficient by four. And then we see we also changed the number of oxygens on the right. So now we have four there. What we need to do next is we need to balance our oxygens and our hydrogens. And so what we can do is we can essentially essentially add a four to our water. And then we do that, we change the number of hydrogens and oxygens. And now instead of 12 hydrogens, we have 16, we have 18, excuse me. And for oxygens, we have four. And so lastly, for to get from two hydrogens to 18, we just simply add a nine to our hydrogen gas. And then we get that the balanced equation is be following. And with that, we have solved the problem overall, I hope this helped. And until next time.