Based on effective nuclear charge (Z_eff), which ion is the strongest oxidizing agent? 

(a) Cu²⁺

(b) Ni²⁺

(c) Fe²⁺

(d) Mn²⁺

Video transcript

Welcome everyone. Our next problem says, identify the ion with the highest oxidizing power. AC R three plus BC 03 plus CFE three plus and DT I three plus. So let's think about what would give an ion the highest oxidizing power. So this would mean that it has a great likelihood of oxidizing something and when something is oxidized, it loses electrons. So something with the highest oxidizing power would mean it has the greatest tendency to take electrons from another atom. So what we'd be looking at is the periodic trends of electron negativity because the more strong that attractive force on the electrons, the more likely your atom will be to attract electrons. So let's first think about where on the periodic table our atoms are and our answer choices and they are all in row four in the transition metal section. So I'm at a deep walk. So if I draw sort of rough two parallel lines, basically representing that D block and write them in order I have T I titanium as the farthest to the left, then chromium cr then iron fe and then the co which is cobalt. So let's think about our electron negativity train trend in the period table as we go from left to right electronegativity increases. That's because we're not adding any electrons into outer shells, not having any increased shielding from inner electrons. But the z effective Zeff in a subscript is increasing as you add more and more protons to the nucleus. So creating that greater attractive force, we also know that electron negativity will increase going up within the columns of the periodic table. But that's not relevant to this question because we're all in the same row. So let's put them in order and think about the ion, the highest oxidizing power most likely to take electrons, the most electron would be co cobalt as the farthest to the right in our grouping. So choice BC 03 plus is our ion with the highest oxidizing power. See you in the next video.