What constant current (in amperes) is required to produce aluminum by the Hall–Héroult process at a rate of 40.0 kg/h?

Video transcript

Hello. In this problem we are asked what amount of constant current in Amperes is needed to generate silver at a rate of 20 kg/h. Using this melting process. So in the smelting process, silver ions are going to be reduced to form silver medal. Call that a fair day tells us that the charge and columns Permal of electrons also recall that an ampere is equal to a per second. So this is our target. We're trying to convert our units from kg of silver per hour, two columns per second. So let's consider a path that we could take. So in our numerator we want to convert from kilograms of silver Discovered that two g of silver And then two moles of silver. Once I know moles of silver, I can relate it to the moles of electrons and then once they know moles of electrons, I can make use of the fair day to find columns and so now I have what I need in the numerator. The denominator. Then I'm gonna convert my hours, two minutes And then two seconds. So we have 20 programs of silver per hour. Take care of the denominator units. First, the one hour is 60 minutes in one minute, 60 seconds. Our units of hours and minutes cancels were left for seconds in the denominator, which is what we need for time, convert our mass from kilograms, two g. One program is to go to 1000 g. Then I go from g to moles. So one mole of silver has a mass of 107.868 g And then for every one mole of silver that is produced require one mole of electrons. And using the fair day, Then one more electrons has a charge of 96,500 Poland. So our kilograms of silver cancels grams of silver cancels, molds of silver cancels holes of electron cancels. And we're left with then columns per second. This works out to 4970 times per second, so we can restate this in terms of amperes, The sand is equal to 4.97 Times 10 to the 3rd And peers. And so this is the ground of constant current that we would need to generate silver at a rate of 20 kg per hour using this multi process. This corresponds then to answer B. Thanks for watching. Hope this helps