In order to charge a lead storage battery (Section 19.10) 500.0 g of PbSO₄(s) must be converted into PbO₂(s) and Pb(s). (a) Does the reaction represent an electrolytic or galvanic cell?

Video transcript

Hello everyone in this problem being told that the H G to c l t s l is converted into HD liquid and cl two gas and an experiment we're being asked here is the overall reaction, a galvanic cell or an electrolytic cell. So here let's first recognize what our half reactions are starting with our cathode side. So for the cathode we have our H G two cl two, which is a solid, we're gonna go and add two electrons to this, which yields then the two moles of H G As well as two moles of RCL -. The state of reduction potential here is equal to 0. volts. So these equations as well as the standard reduction potential values are just the values that I have. But of course you can either find this on your own, given to you by professor or even found online. Alright, so continue on then from an outside that we have here, this is equal to two moles of my cl minus which is acquis This yields our one mole of cl two in its gaseous state as well as two electrons. The standard reduction potential for this half reaction is 1. volts. Alright, so from my S. O. They're creating for this is equal to the reduction potential of my cathode minus. The reduction potential of my a node. Of course we do have these values. Let's go ahead and plug that in. So for my cathode side that is 0.28V. And then for my an outside that is 1.36V. Once I put this value into my calculator received, that my sl value is equal to negative 1.08V. Since our sl value is less than zero. So a negative value, of course, this means that we have and electronic, or each electrolytic cell, and this right here is going to be my final answer for this problem.