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Ch.18 - Thermodynamics: Entropy, Free Energy & Equilibrium

Chapter 18, Problem 126a

Trouton's rule says that the ratio of the molar heat of vaporization of a liquid to its normal boiling point (in kelvin) is approximately the same for all liquids: ∆Hvap/Tbp ≈ 88 J/(K*mol) (a) Check the reliability of Trouton's rule for the liquids listed in the following table.

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well every once in this video we're being told that according to tunes rule that all liquids have a roughly constant ratio between their molar heat of vaporization and a normal boiling point measuring kelvin's. So that is being equal to the value of 88 joules per kelvin times small. We want to go ahead and verify tunes rule by using this table here and calculate all these values given the boiling point and the delta age of vaporization. So let's first off and start off with calculating for these values then. So for period in which is the first one that we have, we see that we want the values of temperature to be in kelvin units were given this in degrees Celsius. So for parenting as 115.23 degrees Celsius. How can convert this into kelvin's by adding 273.15. We put that into the calculator. We see that we get a value of 388.38 kelvin's not something from my ratio here, That is the delta H of vaporization over the boiling point temperature. So we see for our numerator here, we're starting off with the 35.09. We can see that our units given is our killer joules per mole but we want our final to be in jewels here. So we're gonna go ahead and convert this into jewels. Just all on the top here. So for every 1000 jewels we have one kill a jewel that's on the top and the bottom. We just have our temperature and we resolve that to be 3 88. Calvin's gonna see here if we do this unit conversion on the numerator, that kilo jewel unit will cancel. Alright so once I put all these values into my calculator I get the final value To be 90.35 jewels her Kelvin times more. Alright let me just go ahead and scroll down and we're gonna go ahead and go next with the dye, chloral methane again we're gonna start off with converting our temperature units. So for declaring methane this is given to us a 40.0 degrees Celsius. We go ahead and add 273.15 and this gives us a value of 313.15 Calvin's. Now for my ratio here the delta H. Of vaporization over our boiling point temperature. So for my delta H. here I'm given the value of 28.06 killer joules per mole. Again we want to convert this into jewels. So for every 1000 jewels that we have, we have one killer jewel. And now for a temperature of course was plugging that in 2313. Calvin's again you can see that the killer jewel unit will cancel. But to put that into my calculator I get the value of 89.61 joules per kelvin times. Alright continuing on we can now move on to final. So from a temperature that's given to us for a final we have 181. degrees Celsius. I go ahead and add 300 or 273.15. This gives a value for a final to be 455.0 to Calvin's. Now from a ratio of delta H of vaporization over my boiling point temperature For my final I'm given the Delta H value to be 45.69 killer jewels promote. So covering this individuals, we have 1000 joules per one killer jewel For my temperature that sorry, software right above. That's 455.0 to Calvin's. You see that the kill Jules unit will cancel. And then from a numerical values once I put that into my calculator, I get this ratio to be 100.41 joules per kelvin times more. All right now moving on to the next molecule that is going to be tall. Ewing. Alright, so the temperature that I'm given for Halloween is 100 and 10.63 degrees Celsius mounting 273.15 to govern this into Calvin's. That value is 3 83.78 kelvin's. Now for my ratio here that is delta H of vaporization over my boiling point temperature. So they given delta H value is 33. killer jewels per moment. Again. Gonna convert this to jules to 1000 joules per one killer jewel. My temperature is 383. kelvin's. We can see here that the kill jewel units will cancel. Now. Putting this into my calculator. I can get my ratio to be 86.46 joules per kelvin times more and last molecule that we have going on here, that's going to be CCM. So from a temperature that's given, that's 670.8 degrees Celsius riding 273.2 15 this gives us 90 or 943.95 kelvin's. Now for my ratio the delta H of vaporization over my boiling point temperature. So the delta age of vaporization given is 60, Sorry that is 68 0.31. Kill jules per mole to go ahead and multiply this and cancel out our killer jewels to give us jules from our temperature of boiling point diocese 943. kelvin's. So you can see here that the killer jewel unit will cancel. This gives us a final value then of 72.37. And units being jewels per Kelvin times more. Go ahead again. Just scroll down. So you see it from all these values then that my di chloral methane. My fennel and my time doing Has a delta age of vaporization over boiling point temperature to be about or close enough to 88 jules for kelvin times more. So we say that Trans role is reliable for these goods. But with Period Ng and with CCM, this deviates from Truman's rule, so we can see that this or rather this here. This does obey true or this stays away from Sharon's rule, but this one does prove true. His role is reliable.
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Textbook Question

Trouton's rule says that the ratio of the molar heat of vaporization of a liquid to its normal boiling point (in kelvin) is approximately the same for all liquids: ∆Hvap/Tbp ≈ 88 J/(K*mol) (b) Explain why liquids tend to have the same value of ∆Hvap/Tbp.

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Textbook Question
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