The following pictures represent aqueous solutions of three acids HA1A = X, Y, or Z2; water molecules have been omitted for clarity.

(e) What is the percent dissociation in the solution of HZ?

Video transcript

Hello in this problem we are told the diagrams below to pick solutions of three acids H. X. Where X equals A. B or C. For simplicity, water molecules are not shown in the diagram we're told to determine the percent organization of HB. So since we're just concerned with the present organization of H. B. We're going to focus on this central diagram. Our acid H. B. Then we'll undergo hydro sis. That means it will react with water form hydrogen mines and the conjugate base of our acid we call them. The percent organization is equal to the concentration of our hydrogen mines by by the concentration of our acid initially Times 100%. So when looking at the central diagram, we see that we have 1, 2, 3, 4 adjoining mines. The concentration of the conjugate base should be the same right? Because for every one mole of our acid that associates, we form one mole of hydrogen mines and one mole of our conjugate base. This is also equal to four. And so we see those four within the diagram as well. And then we have leftover we have then eight molecules of our associated acid. So before our assets associated, we would have had an initial amount of four plus eight. That's 12. So our percent organization then Will be equal to four which is concentration of our adjoining mines divided by our initial concentration of our acid, which would be 12, multiplied by 100%. This works out to 33%. aN:aN:000NaN So% and this corresponds to answer a thanks for watching Hope.