For each of the following equilibria, write the equilibrium constant expression for Kc. Where appropriate, also write the equilibrium constant expression for Kp. (a) Fe2O31s2 + 3 CO1g2 ∆ 2 Fe1l2 + 3 CO21g2

Video transcript

Hello. Everyone in this video trying to write the equilibrium constant expressions for K. S. C and K F P. Of the reversible reaction given to us here. So KFC is expressed in molar concentrations and K F P is expressed in pressure pressures of the gasses in a closed system. Let's first go ahead and write out this ratio for each. So for the equilibrium constant KFC here, that's equal to the concentration of our products, raise your power of its coefficients all over the concentration of our reactant race to its coefficients. And then now for K F P, that's equal to the partial pressure of our products, raised to the power of its coefficients over the partial pressure of the reactant, raised to power of its coefficients. So again each concentration or partial pressure is raised to the coefficients of each gaseous species in the reaction. So let's go ahead and utilize our chemical equation here. We see that from our chemical equation, our reaction that our products is F. E. O. And its liquid state and S. 02 in its gaseous state. And then for our reactant we have F. E. S in its solid state And 0. 2 gas. Alright, so pure liquids and solids are not included in the equilibrium constant expressions so we can basically kind of ignore our liquid, ignore are solid. So then this makes us our lives a little bit easy here when we're filling out these here, let's go ahead and do this in red. So our KFC is an equal to the concentration of S. 02 because that's the only product that we're concerned about raising the power of two, since I have a coefficient of two and then all over the concentration of CO. Two raised to the power of three. And now for our K. P. This is the partial pressure of S. O. To raise your power of two Over the partial pressure of 0.2 raised to the power of three. So this here is going to be my final equilibrium, causing expressions for the reversible reaction.