For each of the equilibria in Problem 15.56, write the equi-librium constant expression for Kp and give the equation that relates Kp and Kc. (a)

Video transcript

Hello in this problem, we are asked to write the expression for the equilibrium constant in terms of pressure. And provide an equation that relates the equilibrium constant terms of pressure to that. In terms of concentration for the reaction between ethane and flooring to form methane and hydrogen chloride gas. Recall that pure solids and liquids don't appear in the equilibrium constant inspiration. And so when we write the equilibrium constant expression, we are going to eliminate the plural ethane. So the equilibrium constant is the partial pressure of hygiene chloride to the one power divided by partial pressure of that same to the one power times the partial pressure of pouring to the one power. So this is our equilibrium constant expression in terms of pressure. The next thing we're asked to find is to relate the equilibrium constant in terms of pressure to that. In terms of concentration, recall that K. P. Is equal to K. C. Times the gas constant times temperature to the delta end our delta an is the moles of gaseous products minus moles of gaseous reactant. In this problem we have one more gaseous products and we have two moles of gaseous reactant. So it works out to 1 -2 which is -1. So our equilibrium constant, terms of pressure is equal to that. In terms of concentration times gas constant times temperature to the naked one power. You can write this as K. P. Is equal to K. C. Over R. T. So our equilibrium constant in terms of pressure is related to that in terms of concentration by dividing the equilibrium constant. In terms of concentration by gas constant divided by temperature. Thanks for watching. Hope this helps.