Skip to main content
Ch.1 - Chemical Tools: Experimentation & Measurement

Chapter 1, Problem 117

Brass is a copper–zinc alloy. What is the mass in grams of a brass cylinder having a length of 1.62 in. and a diameter of 0.514 in. if the composition of the brass is 67.0% copper and 33.0% zinc by mass? The density of copper is 8.92 g/cm3, and the density of zinc is 7.14 g/cm3. Assume that the den-sity of the brass varies linearly with composition.

Verified Solution
Video duration:
4m
This video solution was recommended by our tutors as helpful for the problem above.
1339
views
Was this helpful?

Video transcript

Hey everyone, we're told that in var is an iron nickel alloy and the composition of in Hvar is 64% iron with a density of 7.86 g per cubic centimeters and 36% nickel with a density of 8.90 g per cubic centimeters by mass, calculate the mass of an Inn var cylinder in grams. That is 1.95 inches in length and 0.675 inches in diameter. Assume that its density changes linearly with composition first. Let's go ahead and calculate the average density of N var. We can do so by multiplying our percentages by its respective density. So starting off with our iron, we can convert that percentage into its decimal form. So that will be 0.640. And we're going to multiply that by 7.86 g per cubic centimeters. Next we're going to add our percent nickel, converting our 36% into its decimal form. We have 0.360. And we're going to multiply that by its density of 8.90 g per cubic centimeters. This will get us to an average density of 8.2344 g per cubic centimeters. Next we want to calculate the volume of our cylinder as we've learned, the formula is going to be volume equals pi times radius squared times height 1st. Let's go ahead and get our height and we want all of our units to be consistent. So we will convert our height and our radius into centimeters. Starting with our height, we were told that we had 1.95" in length. Using our conversion factors, we know that per one inch we have 2. cm. Now when we calculate this out and cancel out our unit, we end up with a height of 4. cm. Next calculating our radius, we were told that we had 0.675 in in diameter. Since this is in diameter, we want to divide this by two in order to get our radius again. Using our conversion factor We know that 1" contains 2.54 cm. So when we calculate this out, we end up with a total of 0. cm. Now to calculate our volume, we're going to plug in our values, we have our pie and we're going to multiply this by our radius squared which is 0. cm. And we're going to square that, Multiplying this by our height of 4.953 cm. And this will get us to a volume of 11.4349 cc. Now that we have our volume. Let's go ahead and calculate our mass. To calculate our mass. We're going to take 11.4349 cubic centimeters which was our volume. And we're going to use dimensional analysis here as we calculated in our average density of in var. We know that we had 8.2344 g per one cc. So when we calculate this out, we end up with a mass of 94.2 g. And this is going to be our final answer. Now, I hope that made sense and let us know if you have any questions.
Related Practice
Textbook Question
At a certain point, the Celsius and Fahrenheit scales 'cross,' giving the same numerical value on both. At what tempera-ture does this crossover occur?
860
views
Textbook Question
Imagine that you place a cork measuring 1.30 cm * 5.50 cm * 3.00 cm in water and that on top of the cork you place a small cube of lead measuring 1.15 cm on each edge. The density of cork is 0.235 g/cm3, and the density of lead is 11.35 g/cm3. Will the combination of cork plus lead float or sink?
1696
views
Textbook Question
A calibrated flask was filled to the 25.00 mL mark with ethyl alcohol. By weighing the flask before and after add-ing the alcohol, it was determined that the flask contained 19.7325 g of alcohol. In a second experiment, 25.0920 g of metal beads were added to the flask, and the flask was again filled to the 25.00 mL mark with ethyl alcohol. The total mass of the metal plus alcohol in the flask was determined to be 38.4704 g. What is the density of the metal in g/mL?
578
views
Textbook Question

Ocean currents are measured in Sverdrups (sv) where 1 sv = 109 m3/s. The Gulf Stream off the tip of Florida, for instance, has a flow of 35 sv. (a) What is the flow of the Gulf Stream in milliliters per minute?

758
views
Textbook Question

Ocean currents are measured in Sverdrups (sv) where 1 sv = 109 m3/s. The Gulf Stream off the tip of Florida, for instance, has a flow of 35 sv. (b) What mass of water in the Gulf Stream flows past a given point in 24 hours? The density of seawater is 1.025 g/mL.

496
views
Textbook Question

Ocean currents are measured in Sverdrups (sv) where 1 sv = 109 m3/s. The Gulf Stream off the tip of Florida, for instance, has a flow of 35 sv. (c) How much time is required for 1 petaliter (PL; 1 PL = 1015 L) of seawater to flow past a given point?

940
views