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Ch.2 - Atoms, Molecules & Ions
Chapter 2, Problem 154

What are the formulas of the compounds formed from the following ions? (a) Ca2+ and Br- (b) Ca2+ and SO42- (c) Al3+ and SO42-

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Identify the charges on each ion: Ca^{2+}, Br^{-}, SO_4^{2-}, and Al^{3+}.
For each pair of ions, balance the total positive and negative charges to ensure the compound is neutral.
For (a) Ca^{2+} and Br^{-}, determine how many Br^{-} ions are needed to balance the charge of one Ca^{2+} ion.
For (b) Ca^{2+} and SO_4^{2-}, check if the charges are already balanced or if any adjustments are needed.
For (c) Al^{3+} and SO_4^{2-}, find the smallest number of each ion needed to balance the charges, using the least common multiple if necessary.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Ionic Compounds

Ionic compounds are formed when cations (positively charged ions) and anions (negatively charged ions) combine. The overall charge of the compound must be neutral, meaning the total positive charge from cations must balance the total negative charge from anions. Understanding how to combine these ions based on their charges is essential for determining the correct formulas of the resulting compounds.
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Charge Balance

Charge balance is a fundamental principle in chemistry that dictates how ions combine to form neutral compounds. For example, a Ca<sup>2+</sup> ion has a +2 charge, while a Br<sup>-</sup> ion has a -1 charge. To achieve neutrality, two Br<sup>-</sup> ions are needed to balance one Ca<sup>2+</sup> ion, resulting in the formula CaBr<sub>2</sub>.
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Polyatomic Ions

Polyatomic ions are ions composed of two or more atoms that are covalently bonded and carry a net charge. For instance, the sulfate ion (SO<sub>4</sub><sup>2-</sup>) has a -2 charge. When combining polyatomic ions with cations, it is crucial to consider the overall charge of the polyatomic ion to ensure the final compound is electrically neutral, as seen in the formation of CaSO<sub>4</sub> and Al<sub>2</sub>(SO<sub>4</sub>)<sub>3</sub>.
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