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Ch.3 - Chemical Reactions and Reaction Stoichiometry
Chapter 3, Problem 82b

Solutions of sulfuric acid and lead(II) acetate react to form solid lead(II) sulfate and a solution of acetic acid. If 5.00 g of sulfuric acid and 5.00 g of lead(II) acetate are mixed, calculate the number of grams of lead(II) acetate present in the mixture after the reaction is complete.

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Write the balanced chemical equation for the reaction: \( \text{H}_2\text{SO}_4 + \text{Pb(CH}_3\text{COO)}_2 \rightarrow \text{PbSO}_4 + 2\text{CH}_3\text{COOH} \).
Calculate the molar mass of sulfuric acid (\( \text{H}_2\text{SO}_4 \)) and lead(II) acetate (\( \text{Pb(CH}_3\text{COO)}_2 \)).
Determine the number of moles of sulfuric acid and lead(II) acetate using their respective masses and molar masses.
Identify the limiting reactant by comparing the mole ratio from the balanced equation to the moles calculated.
Calculate the amount of lead(II) acetate remaining after the reaction by using the stoichiometry of the reaction and the initial moles of the limiting reactant.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Stoichiometry

Stoichiometry is the calculation of reactants and products in chemical reactions based on the balanced chemical equation. It involves using mole ratios derived from the coefficients of the balanced equation to determine how much of each substance is consumed or produced. Understanding stoichiometry is essential for solving problems related to the amounts of reactants and products in a reaction.
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Limiting Reactant

The limiting reactant is the substance that is completely consumed first in a chemical reaction, thus determining the maximum amount of product that can be formed. Identifying the limiting reactant is crucial for calculating the amounts of products and remaining reactants after the reaction. In this case, it will help determine how much lead(II) acetate remains after the reaction with sulfuric acid.
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Molar Mass

Molar mass is the mass of one mole of a substance, typically expressed in grams per mole (g/mol). It is used to convert between the mass of a substance and the number of moles, which is essential for stoichiometric calculations. Knowing the molar masses of sulfuric acid and lead(II) acetate allows for the determination of how many moles are present in the given masses, facilitating the stoichiometric analysis of the reaction.
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Related Practice
Textbook Question

Solutions of sodium carbonate and silver nitrate react to form solid silver carbonate and a solution of sodium nitrate. A solution containing 3.50 g of sodium carbonate is mixed with one containing 5.00 g of silver nitrate. How many grams of sodium carbonate are present after the reaction is complete? How many grams of sodium nitrate are present after the reaction is complete?

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Textbook Question

Solutions of sodium carbonate and silver nitrate react to form solid silver carbonate and a solution of sodium nitrate. A solution containing 3.50 g of sodium carbonate is mixed with one containing 5.00 g of silver nitrate. How many grams of silver carbonate are present after the reaction is complete?

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Textbook Question

Solutions of sulfuric acid and lead(II) acetate react to form solid lead(II) sulfate and a solution of acetic acid. If 5.00 g of sulfuric acid and 5.00 g of lead(II) acetate are mixed, calculate the number of grams of sulfuric acid and grams of acetic acid present in the mixture after the reaction is complete.

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Textbook Question

When benzene 1C6H62 reacts with bromine 1Br22, bromobenzene 1C6H5Br2 is obtained: C6H6 + Br2¡C6H5Br + HBr (a) When 30.0 g of benzene reacts with 65.0 g of bromine, what is the theoretical yield of bromobenzene?

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Textbook Question

When benzene 1C6H62 reacts with bromine 1Br22, bromobenzene 1C6H5Br2 is obtained: C6H6 + Br2¡C6H5Br + HBr (b) If the actual yield of bromobenzene is 42.3 g, what is the percentage yield?

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Textbook Question

When ethane 1C2H62 reacts with chlorine 1Cl22, the main product is C2H5Cl, but other products containing Cl, such as C2H4Cl2, are also obtained in small quantities. The formation of these other products reduces the yield of C2H5Cl. (a) Calculate the theoretical yield of C2H5Cl when 125 g of C2H6 reacts with 255 g of Cl2, assuming that C2H6 and Cl2 react only to form C2H2Cl and HCl. (b) Calculate the percent yield of C2H5Cl if the reaction produces 206 g of C2H5Cl.

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