(c) During a certain reversible process, the surroundings undergo an entropy change, ΔSsurr = -78 J/K. What is the entropy change of the system for this process?

Video transcript

Hey everyone, we're told that the entropy change of the surroundings for a particular reversible process is negative 85 joules per kelvin determined the entropy change of the system for this process. So this question relates to the second law of thermodynamics, which basically tells us that the entropy change of the universe is equivalent to the entropy change of the system plus the entropy change of the surroundings. And this is going to be equal to zero. And again this is a reversible process. Now if we rearrange this equation a bit, we end up with the entropy change of the system is equal to the negative entropy change of the surroundings. So plugging in the values that they provided to us in our questions them we can solve for the entropy change of our system Which is going to be negative of negative 85 joules per kelvin. So essentially the entropy change of our system is going to be plus 85 jewels per kelvin. And this is going to be our final answer now, I hope that made sense. And let us know if you have any questions