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Ch.19 - Chemical Thermodynamics
Chapter 19, Problem 26b

(b) In a particular spontaneous process the entropy of the system decreases. What can you conclude about the sign and magnitude of ΔSsurr?

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Identify the given information: The entropy of the system (ΔS<sub>sys</sub>) decreases, which means ΔS<sub>sys</sub> is negative.
Recall the second law of thermodynamics, which states that for a spontaneous process, the total entropy change of the universe (ΔS<sub>univ</sub>) must be positive, i.e., ΔS<sub>univ</sub> = ΔS<sub>sys</sub> + ΔS<sub>surr</sub> > 0.
Since ΔS<sub>sys</sub> is negative, ΔS<sub>surr</sub> must be positive to ensure that the sum (ΔS<sub>univ</sub>) is positive for the process to be spontaneous.
Determine that the magnitude of ΔS<sub>surr</sub> must be greater than the magnitude of ΔS<sub>sys</sub> to compensate for the negative ΔS<sub>sys</sub> and still achieve a positive ΔS<sub>univ</sub>.
Conclude that ΔS<sub>surr</sub> is positive and its magnitude is greater than the magnitude of the negative ΔS<sub>sys</sub>.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Entropy (S)

Entropy is a measure of the disorder or randomness in a system. In thermodynamics, it quantifies the number of ways a system can be arranged, with higher entropy indicating greater disorder. For spontaneous processes, the second law of thermodynamics states that the total entropy of an isolated system must increase over time, which is crucial for understanding the behavior of systems in nature.
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Second Law of Thermodynamics

The second law of thermodynamics states that in any spontaneous process, the total entropy of the universe (system plus surroundings) must increase. This principle implies that if the entropy of a system decreases, the entropy of the surroundings must increase by a greater amount to ensure that the overall entropy change is positive, thus driving the spontaneity of the process.
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Second Law of Thermodynamics Example

Gibbs Free Energy (ΔG)

Gibbs free energy is a thermodynamic potential that measures the maximum reversible work obtainable from a system at constant temperature and pressure. It is defined as ΔG = ΔH - TΔS, where ΔH is the change in enthalpy, T is the temperature in Kelvin, and ΔS is the change in entropy. A negative ΔG indicates a spontaneous process, linking the concepts of entropy and energy changes in chemical reactions.
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Related Practice
Textbook Question

The element gallium (Ga) freezes at 29.8 °C, and its molar enthalpy of fusion is ΔHfus = 5.59 kJ/mol. (b) Calculate the value of ΔS when 60.0 g of Ga(l) solidifies at 29.8 °C.

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Textbook Question

Indicate whether each statement is true or false. (c) In a certain spontaneous process the system undergoes an entropy change of 4.2 J/K; therefore, the entropy change of the surroundings must be -4.2 J/K.

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Textbook Question

(a) Does the entropy of the surroundings increase for spontaneous processes?

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Textbook Question

(c) During a certain reversible process, the surroundings undergo an entropy change, ΔSsurr = -78 J/K. What is the entropy change of the system for this process?

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Textbook Question

(a) What sign for Δ𝑆 do you expect when the pressure on 0.600 mol of an ideal gas at 350 K is increased isothermally from an initial pressure of 0.750 atm?

(b) If the final pressure on the gas is 1.20 atm, calculate the entropy change for the process.

(c) Which of the following statements about this process are true? (i) The entropy change you calculated will be the same for at any other constant temperature. (ii) The value of Δ𝑆 you calculated is valid only if the compression is done irreversibly. (iii) If the number of moles of gas being compressed were decreased by a factor of three, the entropy change would increase by a factor of three.

Textbook Question

For the isothermal expansion of a gas into a vacuum, ΔE = 0, q = 0, and w = 0. (b) Explain why no work is done by the system during this process.

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