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Ch.9 - Molecular Geometry and Bonding Theories
Chapter 9, Problem 120

The organic molecules shown here are derivatives of benzene in which six-membered rings are 'fused' at the edges of the hexagons. Structures of naphthalene, phenanthrene, and chrysene, fused benzene derivatives.
(e) Benzene, naphthalene, and anthracene are colorless, but tetracene is orange. What does this imply about the relative HOMO–LUMO energy gaps in these molecules? See the 'Chemistry Put to Work' box on orbitals and energy.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

HOMO-LUMO Gap

The HOMO-LUMO gap refers to the energy difference between the highest occupied molecular orbital (HOMO) and the lowest unoccupied molecular orbital (LUMO) in a molecule. This gap is crucial in determining a molecule's electronic properties, including its color. A smaller gap typically allows for electronic transitions that can absorb visible light, leading to color, while a larger gap results in colorless compounds.
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Aromatic Compounds

Aromatic compounds, such as benzene and its derivatives, are characterized by their stable ring structures and delocalized π-electrons. This delocalization contributes to their unique electronic properties, including stability and specific absorption characteristics. The presence of fused rings, as seen in naphthalene and phenanthrene, can influence the HOMO-LUMO gap and, consequently, the color of the compound.
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Color and Electronic Transitions

The color of a compound is often a result of electronic transitions between energy levels when light is absorbed. If a molecule has a small HOMO-LUMO gap, it can absorb visible light, leading to the appearance of color. In contrast, compounds with larger gaps, like benzene and naphthalene, do not absorb visible light and thus appear colorless, while tetracene's orange color suggests a smaller gap allowing for such transitions.
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Related Practice
Textbook Question

Sulfur tetrafluoride 1SF42 reacts slowly with O2 to form sulfur

tetrafluoride monoxide 1OSF42 according to the following

unbalanced reaction:

SF41g2 + O21g2¡OSF41g2

The O atom and the four F atoms in OSF4 are bonded to a

central S atom.

(e) For each of the molecules you drew in part (d), state how many

fluorines are equatorial and how many are axial.

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Textbook Question
The phosphorus trihalides 1PX32 show the following variation in the bond angle X¬P¬X: PF3, 96.3°; PCl3, 100.3°; PBr3, 101.0°; PI3, 102.0°. The trend is generally attributed to the change in the electronegativity of the halogen. (b) What is the general trend in the X¬P¬X angle as the halide electronegativity increases?
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Textbook Question
Many compounds of the transition-metal elements contain direct bonds between metal atoms. We will assume that the z-axis is defined as the metal–metal bond axis. (d) Sketch the energylevel diagram for the Sc2 molecule, assuming that only the 3d orbital from part (a) is important.
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Textbook Question

The organic molecules shown here are derivatives of benzene in which six-membered rings are 'fused' at the edges of the hexagons.

(b) Suppose you are given a sample of one of the compounds. Could combustion analysis be used to determine unambiguously which of the three it is?

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Textbook Question

Methyl isocyanate, CH3NCO, was made infamous in 1984 when an accidental leakage of this compound from a storage tank in Bhopal, India, resulted in the deaths of about 3800 people and severe and lasting injury to many thousands more. (a) Draw a Lewis structure for methyl isocyanate.

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