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Ch.9 - Molecular Geometry and Bonding Theories
Chapter 9, Problem 120

The organic molecules shown here are derivatives of benzene in which six-membered rings are 'fused' at the edges of the hexagons. Structures of naphthalene, phenanthrene, and chrysene, fused benzene derivatives.
(e) Benzene, naphthalene, and anthracene are colorless, but tetracene is orange. What does this imply about the relative HOMO–LUMO energy gaps in these molecules? See the 'Chemistry Put to Work' box on orbitals and energy.

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Step 1: Understand the concept of HOMO (Highest Occupied Molecular Orbital) and LUMO (Lowest Unoccupied Molecular Orbital) energy gaps. The color of a molecule is related to the energy gap between these orbitals.
Step 2: Recognize that when a molecule absorbs light, an electron is promoted from the HOMO to the LUMO. The energy of the absorbed light corresponds to the energy gap between these orbitals.
Step 3: Note that benzene, naphthalene, and anthracene are colorless, indicating that their HOMO-LUMO energy gaps are relatively large, absorbing light in the ultraviolet region which is not visible to the human eye.
Step 4: Observe that tetracene is orange, implying that its HOMO-LUMO energy gap is smaller than that of benzene, naphthalene, and anthracene. This smaller gap means it absorbs light in the visible region, specifically in the blue-green part of the spectrum, which makes it appear orange.
Step 5: Conclude that as the number of fused benzene rings increases, the HOMO-LUMO energy gap decreases. This trend is due to the increased conjugation and delocalization of π-electrons, which lowers the energy difference between the HOMO and LUMO.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

HOMO-LUMO Gap

The HOMO-LUMO gap refers to the energy difference between the highest occupied molecular orbital (HOMO) and the lowest unoccupied molecular orbital (LUMO) in a molecule. This gap is crucial in determining a molecule's electronic properties, including its color. A smaller gap typically allows for electronic transitions that can absorb visible light, leading to color, while a larger gap results in colorless compounds.
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Aromatic Compounds

Aromatic compounds, such as benzene and its derivatives, are characterized by their stable ring structures and delocalized π-electrons. This delocalization contributes to their unique electronic properties, including stability and specific absorption characteristics. The presence of fused rings, as seen in naphthalene and phenanthrene, can influence the HOMO-LUMO gap and, consequently, the color of the compound.
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Color and Electronic Transitions

The color of a compound is often a result of electronic transitions between energy levels when light is absorbed. If a molecule has a small HOMO-LUMO gap, it can absorb visible light, leading to the appearance of color. In contrast, compounds with larger gaps, like benzene and naphthalene, do not absorb visible light and thus appear colorless, while tetracene's orange color suggests a smaller gap allowing for such transitions.
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Related Practice
Open Question
(b) Make a similar comparison of nitrogen–nitrogen bonds. What do you observe? (d) Propose a reason for the large difference in your observations of parts (a) and (b).
Open Question
(b) Determine ΔH for the atomization of naphthalene using Hess’s law and the data in Appendix C. (ΔHf° of solid naphthalene is 77.1 kJ/mol and the molar heat of sublimation of naphthalene is 72.9 kJ/mol.)
Textbook Question
Many compounds of the transition-metal elements contain direct bonds between metal atoms. We will assume that the z-axis is defined as the metal–metal bond axis. (d) Sketch the energylevel diagram for the Sc2 molecule, assuming that only the 3d orbital from part (a) is important.
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Textbook Question

The organic molecules shown here are derivatives of benzene in which six-membered rings are 'fused' at the edges of the hexagons.

(b) Suppose you are given a sample of one of the compounds. Could combustion analysis be used to determine unambiguously which of the three it is?

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Open Question
Antibonding molecular orbitals can be used to make bonds to other atoms in a molecule. For example, metal atoms can use appropriate d orbitals to overlap with the π*2p orbitals of the carbon monoxide molecule. This is called d-π backbonding. (a) Draw a coordinate axis system in which the y-axis is vertical in the plane of the paper and the x-axis horizontal. Write 'M' at the origin to denote a metal atom. (b) Now, on the x-axis to the right of M, draw the Lewis structure of a CO molecule, with the carbon nearest the M. The CO bond axis should be on the x-axis. (c) Draw the CO π*2p orbital, with phases (see the 'Closer Look' box on phases) in the plane of the paper. Two lobes should be pointing toward M. (d) Now draw the dxy orbital of M, with phases. Can you see how they will overlap with the π*2p orbital of CO? (e) What kind of bond is being made with the orbitals between M and C, σ or π? (f) Predict what will happen to the strength of the CO bond in a metal–CO complex compared to CO alone.
Textbook Question

Methyl isocyanate, CH3NCO, was made infamous in 1984 when an accidental leakage of this compound from a storage tank in Bhopal, India, resulted in the deaths of about 3800 people and severe and lasting injury to many thousands more. (a) Draw a Lewis structure for methyl isocyanate.

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