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Ch.9 - Molecular Geometry and Bonding Theories

Chapter 9, Problem 28a3

The figure that follows contains ball-and-stick drawings of three possible shapes of an AF4 molecule. (a) For each shape, give the electron-domain geometry on which the molecular geometry is based. iii.

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Welcome back everyone. The ball and stick drawing of an X. Y. Three molecule is shown below provide its electron domain geometry from which the molecular geometry of the molecule is derived. We want to recall that in a ball and stick drawing there are no lone pairs drawn. So we don't know if there would be any at all. But telling by the shape of our ball and stick model, we can see that we have a T. Shape. So if our molecular geometry that we observe is T shaped, then that corresponds to the following notation. A X sub three E sub two where X sub three portion of this notation tells us that we have three atoms and the E sub two part of our notation tells us that we have two lone pairs. I'm sorry that is two lone pairs here and in total adding these together we would have a total of five electron domains or electron groups. And so this tells us that our electron geometry Because we have five electron domains. We should recall that this will correspond to a X sub five notation, which tells us that we have therefore tribunal by pyramidal geometry for our electron domain geometry. And this highlighted in yellow would be our final answer, which corresponds to choice D in the multiple choice as the correct answer. So I hope that this made sense. And let us know if you have any questions
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