Skip to main content
Ch.9 - Molecular Geometry and Bonding Theories
Chapter 9, Problem 49c

Consider the molecule BF3. (c) What hybrid orbitals should be constructed on the B atom to make the B–F bonds in BF3?

Verified Solution

Video duration:
43s
This video solution was recommended by our tutors as helpful for the problem above.
Was this helpful?

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Hybridization

Hybridization is the process of combining atomic orbitals to form new hybrid orbitals that can accommodate bonding. In BF3, the boron atom undergoes sp2 hybridization, which involves mixing one s orbital and two p orbitals to create three equivalent sp2 hybrid orbitals. This allows boron to form three sigma bonds with fluorine atoms.
Recommended video:
Guided course
00:51
Hybridization

Molecular Geometry

Molecular geometry refers to the three-dimensional arrangement of atoms in a molecule. In the case of BF3, the sp2 hybridization leads to a trigonal planar geometry, where the three B–F bonds are arranged at 120-degree angles around the boron atom. Understanding molecular geometry is crucial for predicting the shape and reactivity of molecules.
Recommended video:
Guided course
01:33
Molecular Geometry with Two Electron Groups

Bonding and Lone Pairs

In covalent bonding, atoms share electrons to achieve stability. In BF3, boron forms three bonds with fluorine atoms, utilizing its sp2 hybrid orbitals. Importantly, boron has an incomplete octet, as it does not have any lone pairs of electrons, which influences its reactivity and the overall electron deficiency of the molecule.
Recommended video:
Guided course
00:51
Electron Groups, Lone Pairs, and Bonding Groups Example