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Ch.9 - Molecular Geometry and Bonding Theories

Chapter 9, Problem 51b

Indicate the hybridization of the central atom in (b) SeF6

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Hello everyone in this question we're asked to identify the hybridization of the central atom. For each of the molecules, we have a church to l. We have one valence electron for hydrogen. And there's two Plus six valence electrons for oxygen. And this gives us a total of eight. And for the structure we're gonna have oxygen in the center and then two hydrogen atoms coming off of it And each bond contains two electrons. So we have 24 six eight. So I have one two three or electron groups around oxygen. So for the hybridization we're gonna have S Mp three, Our Cl Cl two With four valence electrons for carbon Plus six for oxygen Plus seven for Chlorine. And there's two chlorine And this gives us 24 valence electrons. And for the structure we're gonna have carbon in the center to chlorine coming off of it in a double bonded oxygen. So we have 2468, 10, 12, 14, 16, 18, 20 22, And we have three electron groups around carbon. So our organization is going to be s. p two For XE. F four. We're gonna have eight valence electrons for Xenon Plus seven for Florian. And there's four flooring And that'll give us 36 stainless electrons. And for the structure we're gonna have X. E. In the center and for florian coming off of it We have 2468 10 12 14, 16, 18, 20 22 24 28 30 32 34 and 36. So we're gonna have six electron groups around xenon. So this will give us a hybridization of SP three. Me too. Thanks for watching my video. And I hope it was helpful.