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Ch.8 - Basic Concepts of Chemical Bonding
Chapter 8, Problem 88d

A major challenge in implementing the 'hydrogen economy' is finding a safe, lightweight, and compact way of storing hydrogen for use as a fuel. The hydrides of light metals are attractive for hydrogen storage because they can store a high weight percentage of hydrogen in a small volume. For example, NaAlH4 can release 5.6% of its mass as H2 upon decomposing to NaH(s), Al(s), and H2(g). NaAlH4 possesses both covalent bonds, which hold polyatomic anions together, and ionic bonds. (d) What is the formal charge on hydrogen in the polyatomic ion?

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1
Identify the polyatomic ion in NaAlH_4, which is the AlH_4^- ion.
Recall that the formal charge formula is: \( \text{Formal Charge} = \text{Valence Electrons} - \text{Non-bonding Electrons} - \frac{1}{2} \times \text{Bonding Electrons} \).
Determine the number of valence electrons for hydrogen, which is 1.
In the AlH_4^- ion, each hydrogen is bonded to aluminum, contributing 1 bonding electron per bond. Since hydrogen forms one bond, it has 0 non-bonding electrons.
Apply the formal charge formula for hydrogen: \( \text{Formal Charge} = 1 - 0 - \frac{1}{2} \times 2 = 0 \).

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Formal Charge

Formal charge is a theoretical charge assigned to an atom in a molecule, calculated based on the number of valence electrons, the number of bonds, and the number of non-bonding electrons. It helps in determining the most stable structure of a molecule by indicating how electrons are distributed among atoms. The formula for calculating formal charge is: Formal Charge = Valence Electrons - (Non-bonding Electrons + 1/2 Bonding Electrons).
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Covalent and Ionic Bonds

Covalent bonds are formed when two atoms share electrons, typically between nonmetals, resulting in the formation of molecules. In contrast, ionic bonds occur when electrons are transferred from one atom to another, leading to the formation of charged ions that attract each other, usually between metals and nonmetals. Understanding these bonding types is crucial for analyzing the structure and properties of compounds like NaAlH4.
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Hydrides

Hydrides are compounds formed between hydrogen and other elements, often metals, where hydrogen can exist in various bonding states. In the context of metal hydrides, such as NaAlH4, hydrogen is typically present as a hydride ion (H-), which can influence the compound's stability and its ability to release hydrogen gas. This property is significant for applications in hydrogen storage technologies.
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Related Practice
Textbook Question

(c) The measured dipole moment of BrCl is 0.57 D. If you assume the bond length in BrCl is the sum of the atomic radii, what are the partial charges on the atoms in BrCl using the experimental dipole moment?

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Textbook Question

A major challenge in implementing the 'hydrogen economy' is finding a safe, lightweight, and compact way of storing hydrogen for use as a fuel. The hydrides of light metals are attractive for hydrogen storage because they can store a high weight percentage of hydrogen in a small volume. For example, NaAlH4 can release 5.6% of its mass as H2 upon decomposing to NaH(s), Al(s), and H2(g). NaAlH4 possesses both covalent bonds, which hold polyatomic anions together, and ionic bonds. (b) Which element in NaAlH4 is the most electronegative? Which one is the least electronegative? Which element in NaAlH4 is the least electronegative?

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Textbook Question

A major challenge in implementing the 'hydrogen economy' is finding a safe, lightweight, and compact way of storing hydrogen for use as a fuel. The hydrides of light metals are attractive for hydrogen storage because they can store a high weight percentage of hydrogen in a small volume. For example, NaAlH4 can release 5.6% of its mass as H2 upon decomposing to NaH(s), Al(s), and H2(g). NaAlH4 possesses both covalent bonds, which hold polyatomic anions together, and ionic bonds. (c) Based on electronegativity differences, predict the identity of the polyatomic anion. Draw a Lewis structure for this ion.

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Textbook Question

Although I3- is a known ion, F3- is not. (b) One of your classmates says that F3- does not exist because F is too electronegative to make bonds with another atom. Give an example that proves your classmate is wrong.

Textbook Question

Although I3- is a known ion, F3- is not. (c) Another classmate says F3- does not exist because it would violate the octet rule. Is this classmate possibly correct?

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Textbook Question

Calculate the formal charge on the indicated atom in each of the following molecules or ions: (a) the central oxygen atom in O3 (b) phosphorus in PF6- (c) nitrogen in NO2 (d) iodine in ICl3 (e) chlorine in HClO4 (hydrogen is bonded to O).