Figure 7.4 shows the radial probability distribution functions for the 2s orbitals and 2p orbitals. (b) How would you modify Slater's rules to adjust for the difference in electronic penetration of the nucleus for the 2s and 2p orbitals?

Video transcript

Hi everyone here we have a question asking us to identify the statement that would be a good adjustment to slater's rule. To account for the difference in electron penetration of the nucleus for three S three P and three D. Orbital's use the radial probability distribution curve below for reference. So we have three S. Three P. And three D. So R. N. Is going to equal three because we have three sub shells And in equals three. As electrons have some probability of being closer to the nucleus. This probability of being closer to the nucleus results in a smaller peak. P electrons have a similar condition but they are slightly farther than the smaller S. Peak. So this means that S can slightly shield better than P and P can slightly shield better than D. So let's look at our options here, A assign equally larger shielding values for S. P. N. D. B assign a shielding value of S slightly smaller than that of P. And a value for P smaller than that of D. C assign a shielding value of S slightly larger than that of P. And a value for P slightly larger than that of D. Or D. Assigned equally smaller shielding values for S. P. And D. Our answer here is going to be C. A sign, a shielding value of S slightly larger than that of P. And a value for P slightly larger than that of D. Thank you for watching. Bye.