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Ch.6 - Electronic Structure of Atoms
Chapter 6, Problem 22

It is possible to convert radiant energy into electrical energy using photovoltaic cells. Assuming equal efficiency of conversion, would infrared or ultraviolet radiation yield more electrical energy on a per-photon basis?

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Photon Energy

The energy of a photon is directly related to its frequency and inversely related to its wavelength, as described by the equation E = hν, where E is energy, h is Planck's constant, and ν is frequency. Higher frequency radiation, such as ultraviolet (UV), has more energy per photon compared to lower frequency radiation, like infrared (IR). This fundamental principle is crucial for understanding how different types of radiation can be converted into electrical energy.
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Photovoltaic Effect

The photovoltaic effect is the process by which certain materials convert light energy into electrical energy. When photons strike a photovoltaic cell, they can excite electrons, creating electron-hole pairs that generate a flow of electricity. The efficiency of this conversion depends on the energy of the incoming photons, making it essential to consider the type of radiation when evaluating energy output.
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Energy Conversion Efficiency

Energy conversion efficiency refers to the ratio of useful electrical energy output to the total energy input from radiation. In the context of photovoltaic cells, this efficiency can vary based on the wavelength of the incoming light. Since UV photons carry more energy than IR photons, assuming equal conversion efficiency, UV radiation would yield more electrical energy per photon than IR radiation, highlighting the importance of wavelength in energy conversion.
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