Skip to main content
Ch.6 - Electronic Structure of Atoms
Chapter 6, Problem 89a

Consider a transition in which the electron of a hydrogen atom is excited from n = 1 to n = . (a) What is the end result of this transition?

Verified step by step guidance
1
Identify the initial and final energy levels of the electron. In this case, the electron transitions from the initial level n = 1.
Recognize that the final energy level n is not specified in the problem. To proceed, you would need the correct final energy level.
Understand that the energy difference between these levels determines the energy of the photon involved in the transition. The energy can be calculated using the formula: \( E = E_f - E_i \), where \( E_i \) and \( E_f \) are the initial and final energy states of the electron.
Recall that the energy levels of a hydrogen atom are given by the formula: \( E_n = -\frac{13.6 \text{ eV}}{n^2} \), where n is the principal quantum number.
If the final energy level n were known, you could calculate the energy of the photon emitted or absorbed during this transition using the difference in energy levels formula and then determine whether the electron absorbs or emits a photon.

Verified Solution

Video duration:
1m
This video solution was recommended by our tutors as helpful for the problem above.
Was this helpful?

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Quantum Energy Levels

In quantum mechanics, electrons in an atom occupy discrete energy levels, denoted by quantum numbers (n). For hydrogen, these levels are quantized, meaning an electron can only exist in specific states. The transition from a lower energy level (n=1) to a higher one (n=2, for example) involves the absorption of energy, typically in the form of a photon.
Recommended video:
Guided course
02:55
Principal Quantum Number

Photon Absorption

When an electron transitions from a lower to a higher energy level, it absorbs a photon whose energy matches the difference between the two levels. The energy of the photon is given by the equation E = hf, where E is energy, h is Planck's constant, and f is the frequency of the photon. This process is fundamental in understanding how atoms interact with light.
Recommended video:
Guided course
00:41
Moles and Photon Energy

Excited State

An excited state refers to an electron configuration where an electron has absorbed energy and moved to a higher energy level than its ground state. In the case of hydrogen, when the electron transitions from n=1 to n=2, it is in an excited state. This state is typically unstable, and the electron will eventually return to the ground state, often releasing energy in the form of light.
Recommended video:
Guided course
03:55
Element States of Matter
Related Practice
Open Question
Is the observation that UV-B radiation is a more important cause of sunburn in humans than UV-A radiation consistent with the answer to part (c)?
Textbook Question

The watt is the derived SI unit of power, the measure of energy per unit time: 1 W = 1 J>s. A semiconductor laser in a DVD player has an output wavelength of 650 nm and a power level of 5.0 mW. How many photons strike the DVD surface during the playing of a DVD 90 minutes in length?

2645
views
Textbook Question

In an experiment to study the photoelectric effect, a scientist measures the kinetic energy of ejected electrons as a function of the frequency of radiation hitting a metal surface. She obtains the following plot. The point labeled 'n0' corresponds to light with a wavelength of 542 nm. (a) What is the value of n0 in s - 1?

625
views
Textbook Question

Consider a transition in which the electron of a hydrogen atom is excited from n = 1 to n = . (b) What is the wavelength of light that must be absorbed to accomplish this process?

1090
views
Textbook Question

Consider a transition in which the electron of a hydrogen atom is excited from n = 1 to n = . (d) How are the results of parts (b) and (c) related to the plot shown in Exercise 6.88?

558
views
Textbook Question

The human retina has three types of receptor cones, each sensitive to a different range of wavelengths of visible light, as shown in this figure (the colors are merely to differentiate the three curves from one another; they do not indicate the actual colors represented by each curve):

(c) Explain why the sky appears blue even though all wavelengths of solar light are scattered by the atmosphere.

548
views