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Ch.6 - Electronic Structure of Atoms
Chapter 6, Problem 36

Classify each of the following statements as either true or false: (a) A hydrogen atom in the n = 3 state can emit light at only two specific wavelengths (b) a hydrogen atom in the n = 2 state is at a lower energy than one in the n = 1 state (c) the energy of an emitted photon equals the energy difference of the two states involved in the emission.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Energy Levels in Hydrogen Atom

In a hydrogen atom, electrons occupy discrete energy levels, denoted by quantum numbers (n). The energy of these levels increases with n, meaning that an electron in a higher state (like n=3) has more energy than one in a lower state (like n=1). This concept is fundamental to understanding electron transitions and the emission of light.
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Photon Emission and Wavelengths

When an electron transitions between energy levels in a hydrogen atom, it can emit a photon with a specific wavelength. The emitted wavelength corresponds to the energy difference between the two levels involved in the transition. Therefore, a hydrogen atom in a given state can emit light at specific wavelengths determined by these energy differences.
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Energy of Emitted Photons

The energy of an emitted photon is directly related to the difference in energy between the two electron states involved in the transition. This relationship is described by the equation E = hν, where E is the energy of the photon, h is Planck's constant, and ν is the frequency of the emitted light. This principle is crucial for understanding how light is produced in atomic transitions.
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