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Ch.3 - Chemical Reactions and Reaction Stoichiometry
All textbooksBrown 14th EditionCh.3 - Chemical Reactions and Reaction StoichiometryProblem 111
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Chapter 3, Problem 111

Section 2.9 introduced the idea of structural isomerism, with 1-propanol and 2-propanol as examples. Determine which of these properties would distinguish these two substances: (a) boiling point, (b) combustion analysis results, (c) molecular weight, (d) density at a given temperature and pressure. You can check on the properties of these two compounds in Wolfram Alpha (http://www.wolframalpha.com/) or the CRC Handbook of Chemistry and Physics.

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1
Step 1: Understand the concept of structural isomerism. Structural isomers are compounds with the same molecular formula but different structural arrangements of atoms. 1-propanol and 2-propanol are structural isomers of C3H8O.
Step 2: Consider the boiling point. Structural isomers often have different boiling points due to variations in molecular structure affecting intermolecular forces. Check the boiling points of 1-propanol and 2-propanol to see if they differ.
Step 3: Analyze combustion analysis results. Since both isomers have the same molecular formula, their combustion analysis results (amounts of CO2 and H2O produced) will be identical, as combustion depends on the molecular formula.
Step 4: Evaluate molecular weight. Both 1-propanol and 2-propanol have the same molecular formula, C3H8O, and thus the same molecular weight. This property cannot distinguish between them.
Step 5: Examine density at a given temperature and pressure. Density can vary between structural isomers due to differences in molecular packing and structure. Check the densities of 1-propanol and 2-propanol under the same conditions to determine if they differ.
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