Write out the ground-state electron configurations of b. Ru²⁺

Video transcript

Hello, everyone. Today, we have the following problem provide the ground state electron configuration of the ion odium two plus. And then we have various and choices here all using the noble gas configuration using krypton. So Rhodium is in the period five group eight B on the periodic table. And we already know that we are using krypton, we will put that in brackets. And this is the noble gas configuration where when we use the noble gas that comes just before rhodium, which is krypton. And then following the rest of the electron configuration for neutral rhodium, we will enter the S orbital. So five S one. So the fifth period and then we will have four D eight as we enter the D group. Now, that's the electron configuration for neutro odium. So that aligns with in a. So intro A is not correct. So for Rhodium two plus, this involves losing two electrons from the highest energy orbital or orbitals. And we see that that is the five S and the four D orbitals. If we remove one electron from the five S one and one from the for de orbital, that leaves us with a configuration, a noble gas configuration of krypton and brackets followed by four D seven or answer choice B as our answer. And with that, we have solved the problem overall. I hope this helped. And until next time.