Skip to main content
Ch.20 - Electrochemistry
Chapter 20, Problem 116

Cytochrome, a complicated molecule that we will represent as CyFe2+, reacts with the air we breathe to supply energy required to synthesize adenosine triphosphate (ATP). The body uses ATP as an energy source to drive other reactions (Section 19.7). At pH 7.0 the following reduction potentials pertain to this oxidation of CyFe2+: O21g2 + 4 H+1aq2 + 4 e- ¡ 2 H2O1l2 Ered ° = +0.82 V CyFe3+1aq2 + e- ¡ CyFe2+1aq2 E°red = +0.22 V (a) What is ∆G for the oxidation of CyFe2+ by air? (b) If the synthesis of 1.00 mol of ATP from adenosine diphosphate (ADP) requires a ∆G of 37.7 kJ, how many moles of ATP are synthesized per mole of O2?

Verified step by step guidance
1
Step 1: Identify the half-reactions involved in the oxidation of CyFe^{2+} by O_2. The given half-reactions are: (1) O_2(g) + 4H^+(aq) + 4e^- \rightarrow 2H_2O(l) with E_{red}^\circ = +0.82 \text{ V} and (2) CyFe^{3+}(aq) + e^- \rightarrow CyFe^{2+}(aq) with E_{red}^\circ = +0.22 \text{ V}.
Step 2: Determine the overall cell reaction by reversing the second half-reaction (since it is an oxidation) and adding it to the first half-reaction. The oxidation reaction is: CyFe^{2+}(aq) \rightarrow CyFe^{3+}(aq) + e^-.
Step 3: Calculate the standard cell potential (E_{cell}^\circ) by subtracting the reduction potential of the oxidation half-reaction from the reduction potential of the reduction half-reaction: E_{cell}^\circ = E_{red}^\circ (O_2) - E_{red}^\circ (CyFe^{3+/2+}).
Step 4: Use the Nernst equation to calculate \Delta G^\circ for the overall reaction: \Delta G^\circ = -nFE_{cell}^\circ, where n is the number of moles of electrons transferred (4 in this case) and F is the Faraday constant (96485 C/mol).
Step 5: To find how many moles of ATP are synthesized per mole of O_2, divide the \Delta G^\circ of the reaction by the \Delta G required to synthesize 1 mole of ATP (37.7 kJ/mol). This will give the number of moles of ATP produced per mole of O_2.

Verified Solution

Video duration:
4m
This video solution was recommended by our tutors as helpful for the problem above.
Was this helpful?

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Reduction Potentials

Reduction potentials indicate the tendency of a chemical species to gain electrons and be reduced. A higher reduction potential means a greater likelihood of reduction occurring. In electrochemistry, these values are crucial for determining the direction of electron flow in redox reactions, which is essential for calculating Gibbs free energy changes.
Recommended video:
Guided course
01:10
Standard Reduction Potentials

Gibbs Free Energy (∆G)

Gibbs free energy is a thermodynamic quantity that measures the maximum reversible work obtainable from a thermodynamic system at constant temperature and pressure. The change in Gibbs free energy (∆G) during a reaction indicates whether the process is spontaneous (∆G < 0) or non-spontaneous (∆G > 0). It is calculated using the equation ∆G = -nFE, where n is the number of moles of electrons transferred, F is Faraday's constant, and E is the cell potential.
Recommended video:
Guided course
01:51
Gibbs Free Energy of Reactions

ATP Synthesis

Adenosine triphosphate (ATP) is the primary energy carrier in cells, synthesized from adenosine diphosphate (ADP) and inorganic phosphate (Pi) through processes like oxidative phosphorylation. The synthesis of ATP is coupled to exergonic reactions, such as the oxidation of cytochromes, which release energy. Understanding the relationship between the energy released in redox reactions and the energy required for ATP synthesis is key to determining how many moles of ATP can be produced from a given reaction.
Recommended video:
Guided course
03:05
Spontaneity of Processes Example
Related Practice
Textbook Question

Aqueous solutions of ammonia 1NH32 and bleach (active ingredient NaOCl) are sold as cleaning fluids, but bottles of both of them warn: 'Never mix ammonia and bleach, as toxic gases may be produced.' One of the toxic gases that can be produced is chloroamine, NH2Cl. (e) Is N oxidized, reduced, or neither, upon the conversion of ammonia to nitrogen trichloride?

347
views
Open Question
A voltaic cell is based on Ag+ (aq) > Ag (s) and Fe3+ (aq) > Fe2+ (aq) half-cells. Use S° values in Appendix C and the relationship between cell potential and free-energy change to predict whether the standard cell potential increases or decreases when the temperature is raised above 25 °C.
Open Question
Hydrogen gas has the potential for use as a clean fuel in reaction with oxygen. The relevant reaction is 2 H2(g) + O2(g) → 2 H2O(l). Consider two possible ways of utilizing this reaction as an electrical energy source: (i) Hydrogen and oxygen gases are combusted and used to drive a generator, much as coal is currently used in the electric power industry; (ii) hydrogen and oxygen gases are used to generate electricity directly by using fuel cells that operate at 85 °C. Based on the analysis here, would it be more efficient to use the combustion method or the fuel-cell method to generate electrical energy from hydrogen?
Textbook Question

Cytochrome, a complicated molecule that we will represent as CyFe2+, reacts with the air we breathe to supply energy required to synthesize adenosine triphosphate (ATP). The body uses ATP as an energy source to drive other reactions (Section 19.7). At pH 7.0 the following reduction potentials pertain to this oxidation of CyFe2+: O21g2 + 4 H+1aq2 + 4 e- ¡ 2 H2O1l2 Ered ° = +0.8 (b) If the synthesis of 1.00 mol of ATP from adenosine diphosphate (ADP) requires a ∆G of 37.7 kJ, how many moles of ATP are synthesized per mole of O2?

536
views
Open Question
The standard potential for the reduction of AgSCN(s) is +0.09 V. AgSCN(s) + e⁻ → Ag(s) + SCN⁻(aq). Using this value and the electrode potential for Ag⁺(aq), calculate the Ksp for AgSCN.
Open Question
The Ksp value for PbS(s) is 8.0 * 10^-28. By using this value together with an electrode potential from Appendix E, determine the value of the standard reduction potential for the reaction PbS(s) + 2 e^- → Pb(s) + S^2-(aq).