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Ch.2 - Atoms, Molecules, and Ions
Chapter 2, Problem 12a

Sodium reacts with oxygen in air to form two compounds: sodium oxide and sodium peroxide. In forming sodium oxide, 23.0 g of sodium combines with 8.0 g of hydrogen. In forming sodium peroxide, 23.0 g of sodium combines with 16.0 g of oxygen. (a) What are the mass ratios of oxygen in the two compounds?

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1
Identify the two compounds formed: sodium oxide (Na2O) and sodium peroxide (Na2O2).
Calculate the mass ratio of oxygen in sodium oxide. Given that 23.0 g of sodium combines with 8.0 g of oxygen, the mass ratio of oxygen to sodium in sodium oxide is 8.0 g of oxygen per 23.0 g of sodium.
Calculate the mass ratio of oxygen in sodium peroxide. Given that 23.0 g of sodium combines with 16.0 g of oxygen, the mass ratio of oxygen to sodium in sodium peroxide is 16.0 g of oxygen per 23.0 g of sodium.
Compare the mass ratios of oxygen in the two compounds. This involves comparing the ratio of 8.0 g of oxygen to 23.0 g of sodium in sodium oxide with the ratio of 16.0 g of oxygen to 23.0 g of sodium in sodium peroxide.
Express the mass ratios as a simple ratio or fraction to clearly show the difference in the amount of oxygen combined with a fixed amount of sodium in each compound.

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