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Ch.2 - Atoms, Molecules, and Ions

Chapter 2, Problem 12b

Sodium reacts with oxygen in air to form two compounds: sodium oxide and sodium peroxide. In forming sodium oxide, 23.0 g of sodium combines with 8.0 g of hydrogen. In forming sodium peroxide, 23.0 g of sodium combines with 16.0 g of oxygen. (b) What fundamental law does this experiment demonstrate?

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Everyone in this example, we're told that when phosphorus burns and chlorine gas, a mixture of two chloride compounds are produced, phosphorous tri chloride and phosphorus Penta chloride were told that a 7.45 g of phosphorous reacts with 25.6 g of chlorine to form phosphorous tri chloride. Where on the other hand, 7.45 g of phosphorus reacts with 42.7 g of chlorine gas to form phosphorus Penta chloride. And we need to explain which fundamental law is demonstrated by this observation. So what we should recognize is that we have two different mole ratios. Our first mole ratio is between our phosphorus atoms. Where for the first Adam formed, we have 7.45g of phosphorus That is reacting. And for our second compound forming we also have 7.45 g of phosphorus reacting. And when we divide these two out we get a ratio equal to one. And when we take our mole ratio of our chlorine atoms for our first compound we have according to the prompt 25.6 g of chlorine which for the second compound we will now have 42.7 g of chlorine that forms. And when we take the And so as you can see, we have whole number ratios produced from these masses of our atoms phosphorus and chlorine. And so therefore we can say because we have The whole number ratios here which are 1 - two ratio. This is going to correspond to the law of multiple proportions. And we should recall that the law of multi proportions corresponds to the same two elements, forming More than one compound where different masses of one element combine with the same mass of another element and yield a ratio of small hole numbers. And that is exactly what we've displayed here in our calculation above. So this will complete our example as our final answer being the law of multiple proportions, which is the fundamental law observed here. So this completes this example. If you have any questions, please leave them down below and I will see everyone in the next practice video.
Related Practice
Textbook Question

A 1.0-g sample of carbon dioxide (CO2) is fully decomposed into its elements, yielding 0.273 g of carbon and 0.727 g of oxygen. (a) What is the ratio of the mass of O to C?

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Textbook Question

A 1.0-g sample of carbon dioxide (CO2) is fully decomposed into its elements, yielding 0.273 g of carbon and 0.727 g of oxygen. (b) If a sample of a different compound decomposes into 0.429 g of carbon and 0.571 g of oxygen, what is its ratio of the mass of O to C?

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Textbook Question

A 1.0-g sample of carbon dioxide (CO2) is fully decomposed into its elements, yielding 0.273 g of carbon and 0.727 g of oxygen. If a sample of a different compound decomposes into 0.429 g of carbon and 0.571 g of oxygen, what is its ratio of the mass of O to C? (c) According to Dalton's atomic theory, what is the empirical formula of the second compound?

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Textbook Question

A chemist finds that 30.82 g of nitrogen will react with 17.60, 35.20, 70.40, or 88.00 g of oxygen to form four different compounds. (b) How do the numbers in part (a) support Dalton's atomic theory?

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Textbook Question

In a series of experiments, a chemist prepared three different compounds that contain only iodine and fluorine and determined the mass of each element in each compound: Compound Mass of Iodine (g) Mass of Fluorine (g) 1 4.75 3.56 2 7.64 3.43 3 9.41 9.86 (b) How do the numbers in part (a) support the atomic theory?

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Textbook Question
Discovering which of the three subatomic particles proved to be the most difficult—the proton, neutron, or electron? Why?
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