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Ch.17 - Additional Aspects of Aqueous Equilibria
Chapter 17, Problem 67

Use values of Ksp for AgI and Kf for [Ag(CN)2]- to (a) calculate the molar solubility of AgI in pure water. (b) calculate the equilibrium constant for the reaction AgI(s) + 2 CN⁻(aq) ⇌ [Ag(CN)2]⁻(aq) + I⁻(aq). (c) determine the molar solubility of AgI in a 0.100 M NaCN solution.

Verified step by step guidance
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Step 1: Identify the relevant equilibrium expressions. For AgI, the solubility product (K_{sp}) is given by the expression: K_{sp} = [Ag^+][I^-]. For the complex ion formation, the formation constant (K_f) is given by: K_f = \frac{[Ag(CN)_2^-]}{[Ag^+][CN^-]^2}.
Step 2: Calculate the molar solubility of AgI in pure water. Assume the solubility of AgI is 's' mol/L. Then, [Ag^+] = s and [I^-] = s. Substitute these into the K_{sp} expression to solve for 's'.
Step 3: Write the overall reaction for the dissolution of AgI in the presence of CN^-: AgI(s) + 2 CN^- \rightleftharpoons [Ag(CN)_2]^- + I^-. The equilibrium constant for this reaction (K_{overall}) can be found by multiplying K_{sp} and K_f.
Step 4: Calculate the molar solubility of AgI in a 0.100 M NaCN solution. Assume the solubility of AgI is 's' mol/L. In this case, [CN^-] is approximately 0.100 M. Use the expression for K_{overall} to solve for 's', considering the initial concentration of CN^-.
Step 5: Set up the equilibrium expression for the reaction in the NaCN solution: K_{overall} = \frac{[Ag(CN)_2^-][I^-]}{[CN^-]^2}. Substitute the known values and solve for the molar solubility 's'.