Skip to main content
Ch.14 - Chemical Kinetics
Chapter 14, Problem 71

The following mechanism has been proposed for the gas-phase reaction of H2 with ICl: H2(g) + ICl(g) → HI(g) + HCl(g), HI(g) + ICl(g) → I2(g) + HCl(g). (c) If the first step is slow and the second one is fast, which rate law do you expect to be observed for the overall reaction?

Verified step by step guidance
1
Identify the elementary steps in the proposed mechanism: Step 1: H2(g) + ICl(g) → HI(g) + HCl(g) (slow), Step 2: HI(g) + ICl(g) → I2(g) + HCl(g) (fast).
Recognize that the rate-determining step is the slowest step in the mechanism, which is Step 1 in this case.
Write the rate law based on the rate-determining step. For an elementary reaction, the rate law is determined by the stoichiometry of the reactants in that step. Therefore, the rate law for Step 1 is: rate = k[H2][ICl].
Since Step 1 is the rate-determining step, the overall rate law for the reaction is the same as the rate law for Step 1.
Conclude that the observed rate law for the overall reaction is rate = k[H2][ICl], where k is the rate constant for the slow step.