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Ch.13 - Properties of Solutions

Chapter 13, Problem 53b

Describe how you would prepare each of the following aqueous solutions, starting with solid KBr: (b) 125 g of 0.180 m KBr,

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Hi everyone here we have a question asking us to describe the preparation of a 0.160 morality a GUI solution weighing 263 g. Starting with solid magnesium sulfide. So we're going to use morality to calculate the more the mass fraction. So we have 0. morality magnesium sulfate over one kg of water. We're going to multiply that by .38g of magnesium sulfate, divided by one mole magnesium sulfate. And our moles are going to cancel out here And that equals 19 . g of magnesium sulfate per kilogram of water. So our mass fraction is 19.26, Divided by Plus 19. Equals 0. grams of magnesium sulfate Per one g of Solution. So now we need to calculate the mass in 263 g of solution. So we have 263 grams of solution Times 0. grams of magnesium sulfate Per one g of solution Equals 4.97 g. Our massive water equals 263g -4.97 g Equals 258 g of water. So we need to combine 4.97 g of magnesium sulfate With 258 g of water. And that is our final answer. Thank you for watching. Bye