A 10.0 g block of gold is hammered into a thin gold sheet which has an area of 150 cm2. Given the density of gold is 19.3 g/cm3, what is the approximate thickness of the gold sheet in millimeters?

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Calculate the volume of the gold block using its mass and the density of gold. Use the formula: \( \text{Volume} = \frac{\text{Mass}}{\text{Density}} \).

Substitute the given values into the formula: Mass = 10.0 g and Density = 19.3 g/cm^3 to find the volume in cm^3.

Use the formula for volume of a rectangular prism (or sheet): \( \text{Volume} = \text{Area} \times \text{Thickness} \). Rearrange this to solve for thickness: \( \text{Thickness} = \frac{\text{Volume}}{\text{Area}} \).

Substitute the calculated volume and the given area (150 cm^2) into the rearranged formula to find the thickness in cm.

Convert the thickness from cm to mm by multiplying by 10, since 1 cm = 10 mm.

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