In this example question, it states calculate the uncertainty and velocity of a neutron if the uncertainty in its position is 712 picometers. Here we're told the mass of the neutron is 1.67510 * 10-27 kilograms. All right, so we're going to be utilizing the Heisenberg uncertainty principle to answer this question. Now remember that it's going to be that the uncertainty in our position, which is delta X times the mass of our object, in this case the neutron, times the uncertainty in its velocity, will be greater than or equal to Planck's constant divided by 4 * π.
All we have to do here is fill in the information we know. Let's see. So we know what the uncertainty in the position is at 712 picometers. But remember, we need the units of length to be in meters, not picometers. So we're going to do a conversion here. We have 712 picometers. Remember 1 pico is 10-12, so this is equal to 7.112 * 10-10 meters. So this will be our delta X. Next we're going to say that M represents the mass of our neutron, which were given as 1.67510 * 10-27 kilograms. And then that's going to be times our uncertainty and velocity, which we don't know this would be greater than or equal to.
Remember Planck's constant here, 6.626 * 10-34? Remember the units here are Joules times seconds. Joules itself is equal to kilograms times meter squared over second squared, and that's going to be multiplying by seconds. So one of these seconds cancels out with this second. So the units here will really be kilograms times meter squared over seconds. That's going to be divided by 4 * π. Now what we're going to do here is we're going to try to simplify all of this for ourselves. We're going to multiply these two together. When we multiply them together, that's going to give me 1.1926712 * 10-36. Here it's going to be kilograms times meters, and the only reason I'm doing it in that order is because Planck's constant puts kilograms of four meters squared, and that's going to be times our unknown or uncertainty in velocity, which will be greater than or equal to.
So divide now Planck's constant by 4 Pi. When we do that, that's going to give me 5.2728 * 10-35 kilograms times meter squared over seconds. Finally, we want to isolate the uncertainty in our velocity. So divide both sides now by this 1.1926712 * 10-36 kilograms times meters on both sides. So when we do that here, this cancels out, and then over here kilograms cancel out with kilograms. This meter cancels out with one of these meters, which at the end gives us what? Meters or seconds? Which makes sense because those are the customary units for velocity. So we're going to say here, when we punch that into our calculator, the uncertainty in our velocity will be greater than or equal to 44.2 meters per second. This would be our final answer to this example question.