Here we have to calculate the root mean square speed of NH3 molecules at 50�C. All right, so NH3 is ammonia. And remember root mean square speed, so VRMS equals 3RT/m. Here we're going to say we have temperature of 50�C, so we're going to add 273.15 to that. That gives us 323.15 Kelvin.
Remember, because we're dealing with seed, the R we use is 8.314. Also remember that when we talk about Joules, Joules are kilograms times meters squared over second squared O. Here, if we're dealing with our R constant, which is in joules over moles times K, we can substitute this in for joules, so that becomes kilograms times meters squared over second squared times moles times K. That is all of our units that we have here.
Null times K temperature 323.15 K divided by the molar mass of the gas in kilograms, not grams per mole. So NH3 itself with its one nitrogen and its three hydrogens has a mass of 17.034g per mole. But if we want to do it in kilograms per mole, remember we have 10 to the three grams and then one kilogram grams cancel out. So this is 0.017034 kilograms per mole. So then that is 0.017034 kilograms per mole here.
Then we look and see what units cancel out. So kilograms cancel out with kilograms, moles cancel out with moles, kelvins cancel out with kelvins. So what we have left is meters squared over seconds squared, and if we're taking the square root, that's going to just leave us with meters per second. Here, 50 has one sig fig, but here having one sig fig is not great in terms of calculating our root mean square speed.
So here we're going to disregard sig figs, at least from what's given to us within the question, we're just going to go with 687.9 meters per second. So here I'm using four significant figures because one significant figure is not accurate enough. If we went by one sig fig, this would round up to 700 meters per second, which is a bit different from our actual answer. All right, so just remember the units needed in order to isolate your root mean square speed.