The 'free-base' form of cocaine (C₁₇H₂₁NO₄) and its protonated hydrochloride form (C₁₇H₂₁NO₄) are shown below; the free-base form can be converted to the hydrochloride form with one equivalent of HCl. For clarity, not all the carbon and hydrogen atoms are shown; each vertex represents a carbon atom with the appropriate number of hydrogen atoms so that each carbon makes four bonds to other atoms (e) How many mL of a concentrated 18.0 M HCl aqueous solution would it take to convert 1.00 kilograms (a 'kilo') of the free-base form of cocaine into its hydrochloride form?

Video transcript

Hello everyone. Today we are being asked to determine the volume in middle leaders. So we're going to find a volume of middle leaders of a 17 moller hbr solution that is needed to convert 1.67 kg of a sentinel died. And it's given our Mueller mass into its karmic cilic form. If the reaction between H B. R and the compound has a 1 to 1 mole ratio. So the first thing we wanna do is we know that we have a mass and we need to convert that mass and find milliliters the volume. So we take that 1.67 kg and we have to convert this into grams. Since we have our molar mass and units of grams we can say that one at times 10 to the third grams is equal to one kg. Now we can use our moller mass ratio that we have set up and we can do that by saying that for every one mole of the allied Gives us 135.17 g of that compound. And then we can go ahead and use the multiple ratio and say that one mole of a C to the light gives us one mole of H B R. As indicated in the question stem. Finally we can use the polarity of that HBR and say that for One leader of that HBR We have 17 moles of HBR. And lastly we need this in leaders. So what we're going to do is we are going to place our leaders in the top, we're going to say one millimeter is equal, one mL equal to one times 10 to the negative third leaders. And when all of our units cancel that, we're going to end up with an answer of 727 ml as our final answer. I hope this helped, and until next time.