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Ch.14 - Chemical Kinetics
Chapter 14, Problem 111

The energy of activation for the decomposition of 2 mol of HI to H2 and I2 in the gas phase is 185 kJ. The heat of formation of HI(g) from H2(g) and I2(g) is -5.65 kJ/mol. Find the energy of activation for the reaction of 1 mol of H2 and 1 mol of I2 to form 2 mol of HI in the gas phase.

Verified step by step guidance
1
Identify the given data: the activation energy for the decomposition of 2 mol of HI is 185 kJ, and the heat of formation of HI is -5.65 kJ/mol.
Understand that the activation energy for the reverse reaction (formation of HI) can be found using the relationship between the activation energies of the forward and reverse reactions and the enthalpy change of the reaction.
Calculate the enthalpy change (ΔH) for the formation of 2 mol of HI using the given heat of formation: ΔH = 2 mol × (-5.65 kJ/mol).
Use the equation for the activation energy of the reverse reaction: E_a(reverse) = E_a(forward) - ΔH, where E_a(forward) is the activation energy for the decomposition of HI.
Substitute the known values into the equation to find the activation energy for the formation of HI.