Write a balanced chemical equation for the formation of a polymer via a condensation reaction from the monomers succinic acid 1HOOCCH2CH2COOH2 and ethylenediamine 1H2NCH2CH2NH22.

Video transcript

Hello. Everyone in this video, we're dealing with two monitors that forms a polymer via a condensation reaction. So a conversation reaction is when two molecules combined to form a larger molecule by elimination of a smaller molecule. So I'm just gonna kind of drought and map out the reaction that occurs when we're dealing with these two monomers. And I'll just use reaction a as an example, not that statement is correct or not, but we're just gonna go ahead and use it just for the sake of efficiency. So then we know that our nitrogen atom has a long pair that lone pair attacks this nuclear or electra filic carbon. Then the carbon oxygen double bond breaks and forms a lone pair on this oxygen. So we get something like this. We won't draw out the whole molecule, we'll just have our and we have a central atom carbon with R. O. H. And then R. R. N. H. Two. This nitrogen will now have a positive one formal charge. And because we broke the double bond here, this oxygen will not have three lone pairs and have a negative one formal charge. Of course we know that this auction with three lone pairs does not like what it has so far. So go ahead and want to reform a carbon oxygen double bond and what it ends up kicking out is going to be our smaller group and that's going to be R. O. H. And of course later down line we can go ahead and bring out more of these reactions here but we know that eventually one of the higher regions on this nitrogen will go ahead and break off as well. And if we have our hydrogen H plus carry on with our hydroxide ion that breaks off, then H plus that reacts with O. H minus. We'll go ahead and form H +20. So what we're talking about here when I say that a smaller molecule will detach from this condensation reaction is going to be of HBO. So that's kind of a hint that we can go ahead and use when looking through these four different possibilities for answers. So right off the bat for a then R. 02 is not going to be what we said is going to eliminate its H 20. So A is incorrect. Then with statement be here we see that H 20. Is definitely one of our answers and then scrolling down here for choices C. N. D. We'll see also has our H 20. Being eliminated but D. Does not so D. Is incorrect. So now we're just comparing simply B. M. C. We see here that for C we have a double bond here that kind of just randomly forms. And that's incorrect because this carbon bond actually doesn't is not involved in this reaction. So, a possibility of this double bond forming is close to none. So we say that answer. Choice C. Is also wrong. And that leaves us with answer B. Here. We can see that everything seems to be in the right places, and the molecule that's being eliminated is H 20. As we have predicted. So, statement B is going to be my final answer for this problem.