Use the van't Hoff factors in Table 13.9 to calculate each colligative property: a. the melting point of a 0.100 m iron(III) chloride solution

Video transcript

Hi everyone here we have a question asking what is the melting point of a 0. Morality potassium sulfate solution. Van Hoff factor of potassium sulfate is 2.6. So we're going to assume that it is an aqueous solution, so are melting point equals our freezing point and our freezing point constant Equals 1.86 degrees Celsius per morality. And the freezing point of our solvent is 0°C. So our change in freezing point equals the freezing point of our peer solvent minus the freezing point of our solution. The change in freezing point equals r. Van Hoff factor times are freezing point constant times our morality. So the change in freezing point Equals 2. Times 1.86°C over morality Times 0.128 Morality Equals 0.619°C. The temperature of our solution equals the temperature of our peer solvent minus the change in temperature. So the temperature of our solution Equals 0°C -0.619°C equals negative 0.619 degrees Celsius. And we're going to round that up to 0.62°C. And that is our final answer. Thank you for watching. Bye