A 1.2 m aqueous solution of an ionic compound with the formula MX2 has a boiling point of 101.4 °C. Calculate the van't Hoff factor (i) for MX2 at this concentration.

Video transcript

Hi everyone here we have a question telling us that the boiling point of a 2.4 morality solution of an ionic compound MX three is 103.9°C. And our question is, what is the van Hoff factor I for M X three? So we know that the change in the boiling point equals the boiling point of our solution minus the boiling point of our solvent. The change in boiling point equals the van Hoff factor times the boiling point constant times the morality. So the change in boiling point Equals 103 .9° C -100°C, Which equals 3.9 degrees Celsius. Our boiling point constant equals 0.512 degrees Celsius per morality. So R. I equals R. Change in boiling point divided by our Van Hoff factor times our boiling point constant times our morality, So I equals 3.9°C divided by 0. degrees Celsius per morality Times 2.4 Morality, Which equals 3.2. And that is our final answer. Thank you for watching. Bye.