In this video, we're going to begin our discussion on reducing sugars tests. So it turns out that there are actually several different experimental tests that can detect the presence of reducing sugars, and one of these tests is the Fehling's test for reducing sugars. So, Fehling's test is named after the scientist who helped develop it, and so Fehling's test is really just an experimental color change reaction, and as we'll see, the color is going to change from a blue color to a reddish color in the presence of a reducing sugar. Really this color change reaction is about testing for the presence of reducing sugars.
We'll see that this Fehling's test uses a blue cupric ion solution as the oxidizing agent, and in the presence of a non-reducing sugar, the blue cupric ion is not going to be reduced. That means that the blue cupric ion is going to remain its blue color in the presence of non-reducing sugars. However, when the blue cupric ion is in the presence of reducing sugars, then the blue cupric ion will be reduced and it will ultimately generate this red cupric oxide precipitate.
What you'll notice is that the blue solution in the presence of a reducing sugar will change from a blue color to a red color. So when the color changes to a red color, that indicates the presence of a reducing sugar. Let's take a look down below at our image, and notice up here at the top left, we have a cyclic sugar that is actually a reducing sugar. We can tell that it's reducing because when we look at the anomer carbon here, notice that it's present forming a hemiacetal. Hemiacetals are known to be relatively unstable and can react to generate its linear form again.
Here we have the linear form of the same cyclic sugar, and notice that it has a free aldehyde group that's capable of being oxidized. In the presence of the cupric ion oxidizing agent, the aldehyde group is oxidized, turning into a carboxylic acid. In the process, the ion molecule here is being reduced in its charge, and ultimately, the reduced cupric ion can react to form a cupric oxide precipitate that is going to be a red color.
The idea here is that when there are no reducing sugars, the cupric ion solution is going to remain blue. This is going to be our negative control with no reducing sugars present, and no reducing sugars means that no precipitate is going to form. However, in the presence of a reducing sugar, this cupric ion oxide precipitate is going to form. So, we will get a red color which is our positive control in the presence of reducing sugars, and we will get a red cupric oxide precipitate.
The main summary of the Fehling's test is that if the solution does turn this reddish-brownish brick color, then that indicates the presence of a reducing sugar and if it does not turn this reddish-brownish color over here and it remains blue, then that means that there are no reducing sugars present, and any sugars that are present would be non-reducing. Really it's just a simple color change reaction, and in our next video, we'll be able to talk about another test for reducing sugars called the Benedict's test, which is very similar to the Fehling's test. So, I'll see you guys in our next video.